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cestrela7 [59]
3 years ago
12

What is (10+y)^2-y^2=3x+12 in standard form?

Mathematics
1 answer:
Maru [420]3 years ago
6 0
(10 + y)² - y² = 3x + 12
(10 + y)·(10 + y) - y² = 3x + 12
10² + 20y + y² - y² = 3x +12
100 + 20y = 3x + 12
100 - 12 = 3x - 20y
3x - 20y = 88
3x - 20 y - 88 = 0 (I suppose it is that one, simplifyied and in order of the letters, or that it you at the previous step)



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Dovator [93]
To find probability, you'd have to find the total number of marbles (5+3+6+6=20), and since there are 3 blue marbles, the probability of picking one is 3 out of 20, or 3/20
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8 0
3 years ago
Determine which expression has the greater value: 40-16 +10 or -20 + 18 + 30?
Paul [167]

Answer:

40-16+10

Step-by-step explanation:

40-16+10= 34

-20+18+18= 28

the greater answer is 40-16+10

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4 years ago
How many foci does the graph of a hyperbola have
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Read 2 more answers
Please please help me with this please
ziro4ka [17]

Answer:

y + 20 = 9(x + 2)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the lie

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (- 2, - 20) and (x₂, y₂ ) = (9, 79)

m = \frac{79+20}{9+2} = \frac{99}{11} = 9

Using (a, b) = (- 2, - 20), then

y - (- 20) = 9(x - (- 2)), that is

y + 20 = 9(x + 2)

4 0
3 years ago
The velocity of a car over five hours is given by v(t)=60ln(t+1),0≤t≤5 in kilometers per hour. What is the total distance travel
algol [13]

Step-by-step explanation:

as the velocity is not constant over time, we actually have to integrate v(t) over the interval 0<=t<=5 to get the distance.

v(t) = 60×ln(t + 1)

V(t) = 60 × integral(ln(t + 1)) between 0 and 5.

integral(ln(t + 1)) = (t + 1)ln(t + 1) - t + C

V(t) = 60 × ((t + 1)ln(t + 1) - t + C)

the distance traveled between t = 0 and t = 5 is then

60 × ((5 + 1)ln(5 + 1) - 5 + C) - 60 × ((0 + 1)ln(0 + 1) - 0 + C) =

= 60×(6ln(6) - 5 + C) - 60×(1ln(1) + C) =

= 60×(5.750556815... + C) - 60×C =

= 60×5.750556815... = 345.0334089... ≈ 345 km

7 0
2 years ago
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