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3 years ago

Identify the equation of the circle that has its center at (-16,30) and passes through the origin

Mathematics

1 answer:

dangina [55]3 years ago

3 0

Answer:

(x+16)²+(y-30)²=1156

Step-by-step explanation:

We have given:

center at (-16,30). It means h = -16 and k=30

and it passes through the origin (0,0)

Thus the radius will be distance between (-16,30) and (0,0)

r=√(-16 - 0)²+(30-0)²

r=√256+900

r²=(√1156)²

r²=1156

Now apply standard equation of circle:

(x-h)²+(y-k)² = r²

(x+16)²+(y-30)²=1156

Thus the equation is (x+16)²+(y-30)²=1156 ....

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