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timofeeve [1]
3 years ago
15

Jack's age is three years more than twice his younger brother Jimmy's age If the sum of their ages is at most 18 find the greate

st age that Jimmy could be.
Mathematics
1 answer:
UNO [17]3 years ago
6 0
J + 3 + 2j ≤ 18
3j + 3 ≤ 18
3j ≤ 15
j ≤ 5 
jimmy's age is 5 years or less
You might be interested in
In how many ways can a
Tomtit [17]

Answer:

The answer is 364. There are 364 ways of choosing a recorder, a facilitator and a questioner froma club containing 14 members.

This is a Combination problem.  

Combination is a branch of mathematics that deals with the problem relating to the number of iterations which allows one to select a sample of elements which we can term "<em>r</em>" from a collection or a group of distinct objects which we can name "<em>n</em>". The rules here are that replacements are not allowed and sample elements may be chosen in any order.

Step-by-step explanation:

Step I

The formula is given as

C (n,r) = \frac{n}{r} = \frac{n!}{(r!(n-r)!)}

n (objects) = 14

r (sample) = 3

Step 2 - Insert Figures

C (14, 3) = (\frac{14}{3}) = \frac{14!}{(3!(14-3)!)}

= \frac{87178291200}{(6 X 39916800)}

= \frac{87178291200}{239500800}

= 364

Step 3

The total number of ways a recorder, a facilitator and a questioner can be chosen in a club containing 14 members therefore is 364.

Cheers!

6 0
3 years ago
Divide.<br>(3x4 - 3x2 - 6x - 10) = (x - 2)​
alekssr [168]

Answer:

3x^3 + 6x^2 + 15x + 36 + 62 / 3x^4 +3x^2 +6x + 10

Step-by-step explanation:

Use Syenthetic Division

4 0
3 years ago
I NEED HELP ASAP:
olga55 [171]
First, you have to do some factorization

60 = {1,2,3,4,5,6,10,12,15,20,30,60}
72 = {1,2,3,4,6,8,9,12,18,24,36,72}

the GCF is 12

now we find the number that you multiply by 12 to get 60 and another number to get 72.

12 x 5 = 60
12 x 6 = 72

now we notice if you add 60 + 72, we can now tell that it also equals (12)(5)+(12)(6)= 12(5+6)
6 0
4 years ago
Which of the following is a binomial? <br>A) 8x^5<br>B) 11x+18 <br>C) 14x^2+5x+12 <br>D) 4/x
Citrus2011 [14]

A Binomial is a Polynomial with two terms:

8 0
1 year ago
Camilo practica tiro al blanco. En cada disparo acertado puede obtener 5, 8, o 10 puntos. En su última práctica, su puntuación t
Radda [10]

Answer:

20 disparos

Step-by-step explanation:

Primera etapa es de determinar cuantos tiros de Camilo acertaron al blanco.

Sabemos que en su última práctica, obtuvo 99 puntos con una mezcla de 5, 8 y 10 puntos.  Eso puedo se exprimir así:

5x + 8y + 10x = 99

Sabemos también que el obtuvo tantos tiros de 8 puntos que de 10 puntos, entonces

y = z

Podemos mezclar las 2 ecuaciones y substituir y por z:

5x + 8y + 10y = 99

5x +18y = 99

Una ecuación, dos variables... no es fácil... pero son números pequeños y se puede intentar soluciones.  Entonces, cuantas veces podemos multiplicar 5 y 18 para obtener 99?

El más simple es de hacer la tabla de multiplicación de 18 y ver cual número nos deja con un multiple de 5.

18 x 1 = 18 (99 - 18 = 81, no un multiple e 5)

18 x 2 = 36 (99 - 36 = 63, no un multiple de 5)

18 x 3 = 54 (99 - 54 = 45, SI, un multiple de 5)

18 x 4 = 72 (99 - 72 = 27, no un multiple de 5)

18 x 5 = 90 (99 - 90 = 9, no un multiple de 5)

Entonces, sabemos que y = 3 y z = 3

5x + 18 (3) = 99

5x + 54 = 99

5x = 45

x = 9

El tiró 9 veces por 5 puntos, 3 veces por 8 puntos y 3 veces pour 10 puntos.

En total tiró 15 veces.

Si acertó 75% (3/4) de las veces, cuantos tiros total?

\frac{15}{3/4} = \frac{15 * 4}{3} = 20

Camilo tiró 20 veces en total.

8 0
4 years ago
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