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2 years ago

How do I solve the equation?

Mathematics

1 answer:

trapecia [35]2 years ago

5 0

Answer:

(-3, 5) radius- r= 5

Step-by-step explanation:

x^2+6x+y^2-10y=-9

Rewrite ^2+6x+y^2-10y=-9 in the form of the standard circle equation

(x-(-3))^2+(y-5)^2= 5^2

Therefore the circle properties are:

(a, b)=(-3, 5), r= 5

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3 years ago

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3 years ago

The total length of pencils A, B and C is 29 cm. Pencil a is 11 cm shorter then pencil B, and pencil B is twice as long a pencil

satela [25.4K]

The length of pencil A is 5 cm

Solution:

Let the length of pencil A be "x"

Let the length of pencil B be "y"

Let the length of pencil C be "z"

The total length of pencils A, B and C is 29 cm

Therefore,

length of pencil A + length of pencil B + length of pencil C = 29

x + y + z = 29 ------------ eqn 1

Pencil A is 11 cm shorter then pencil B

x = y - 11 ------- eqn 2

Pencil B is twice as long a pencil C

y = 2z

$z = \frac{y}{2}$ ------ eqn 3

Substitute eqn 2 and eqn 3 in eqn 1

$y - 11 + y + \frac{y}{2} = 29\\\\2y + \frac{y}{2} = 29 + 11\\\\\frac{4y+y}{2} = 40\\\\5y = 80\\\\y = 16$

Substitute y = 16 in eqn 2

x = 16 - 11

x = 5

Thus length of pencil A is 5 cm

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3 years ago