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topjm [15]
3 years ago
6

If it takes a sprinter 10.3 seconds to run a distance of 100m. what is the runners average speed?

Mathematics
2 answers:
Rina8888 [55]3 years ago
5 0
You would do 100/10.3, and get about 9.71m/sec
Firdavs [7]3 years ago
5 0
You would do 100 / 10.3 (speed = distance divided by time)
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a fish tank contains 18 goldfish and 22 guppies . if you randomly select 2 fish what is the probabilty that they are both goldfi
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2/40 I thinks asdfsdf
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3 years ago
Question 2 Multiple Choice Worth 1 points)
Sergio [31]

Answer:

x=11

Step-by-step explanation:

by simplifying we get x=11

4 0
3 years ago
Ava poured 3 gallons of paint equally into 5 cans. How many gallons of paint will there be in each can
FromTheMoon [43]

Answer:

0.6 gallons/can

Step-by-step explanation:

Simply divide the gallons of paint by the number of cans:

\frac{3-gallons-of-paint}{5-cans} = 0.6 gallons/can

5 0
2 years ago
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How to work it out logically? Question a !!!
Arturiano [62]

Answer:

Fencing is done along KL which is (1500+520.8=2020.8 m) from the top left corner and divides the property into half.

Step-by-step explanation:

Given the figure with dimensions. we have to find the area of given figure.

Area of figure=ar(1)+ar(2)+ar(3)

Area of region 1 = ar(ANGI)+ar(AIB)

                          =L\times B+\frac{1}{2}\times base\times height\\\\=[1500\times (5000-2000-1500)]+\frac{1}{2}\times (3000-1500)\times (5000-2000-1500)\\\\=3375000m^2=337.5ha

Area of region 2 = ar(DHBC)

                       =2000\times1500\\\\=3000000m^2=300ha

Area of region 3 = ar(GFEH)

                             (2000+1500)\times 1000\\\\=3500000m^2=350ha

Hence, Area of figure=ar(1)+ar(2)+ar(3)=337.5ha+300ha+350ha

                                                 =987.5 ha

Now, we have to do straight-line fencing such that area become half and cost of fencing is minimum.

Let the fencing be done through x m downward from B which divides the two into equal area.

⇒ Area of upper part above fencing=Area of lower part below fencing

⇒ar(ANGB)+ar(GKLB)=ar(KLCM)+ar(MDCF)\\\\337500+3000x=(3500-x)\times 1000+2000(1500-x)\\\\3375000+3000x=3500000-1000x+3000000-2000x\\\\6000x=315000\\\\x=\frac{315000}{6000}=520.8m

Hence, fencing is done along KL which is (1500+520.8=2020.8 m) from the top left corner and divides the property into half.

7 0
3 years ago
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The number of 5-digit numbers that can be formed if the last digit is odd and no
Softa [21]

Answer:

13,440

Step-by-step explanation:

10 possible digits 0 - 9

5 possible numbers for position 5  (odd digits only)

8 possible numbers for position 1  (cannot be zero or the odd number selected for position 5)

8 possible numbers remain for position 2 (10 minus 2 already selected)

7 possible numbers remain for position 3 (10 minus 3 already selected)

6 possible numbers remain for position 4 (10 minus 4 already selected)

5•8•8•7•6 = 13,440

7 0
3 years ago
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