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UNO [17]
3 years ago
12

Does the equation y = x(x - 3) represent a linear function

Mathematics
1 answer:
Flauer [41]3 years ago
7 0

Answer:

No

Step-by-step explanation:

No. You can see why if you remove the brackets.

y=x^2 - 3x.

A linear function must have x and y with powers of 1. Also it can't something like x^2 - y^2 = 5

x^2 - y^2 = 0 is the only exception I can think of, but that really is a system of equations. If you graph it. you get two equations which cross at 0 and nowhere else.

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If the circumference of a circle is 84.5 ft, find the radius.
Elina [12.6K]

Answer:

13.448, rounded off: 13.5 ft

Step-by-step explanation:

r=\frac{C}{2\pi }

Where r = radius, C = circumference.

r=\frac{84.5}{2\pi } =13.448 = 13.5 ft

6 0
3 years ago
Read 2 more answers
Drag each label to the correct location on the image.
Molodets [167]

Answer:

1 x (4 x 2) = 8

Step-by-step explanation:

1 x (4 x 2) = 8

7 0
2 years ago
What’s the distance between (-9,-3) and y=x-6
jeyben [28]

hopefully this will help :)

8 0
3 years ago
Is 0.84 less than greater than or equal to one half
Neporo4naja [7]
One half is 0.50, so compare 0.84 to 0.50.  Which is true?

0.84 is greater than 0.50
0.84 equals 0.50
0.84 is less than 0.50.

8 0
3 years ago
Read 2 more answers
A system for tracking ships indicated that a ship lies on a hyperbolic path described by 5x2 - y2 = 20. the process is repeated
zysi [14]
Answer:
The ship is located at (3,5)

Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III

Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II

To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.

Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = <span>± </span>√9

We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3

Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5

Based on the above, the position of the ship is (3,5).

Hope this helps :)
8 0
3 years ago
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