Answer: Option A -439
(s o t)(x)=s(t(x))
(s o t)(-7)=s(t(-7))
x=-7→t(-7)=3(-7)→t(-7)=-21
(s o t)(-7)=s(t(-7))=s(-21)
x=-21→s(-21)=2-(-21)^2=2-441→s(-21)=-439
(s o t)(-7)=s(t(-7))=s(-21)=-439
Answer: Option A -439
Answer:
Discontinuity of function occurs when x = 4 or x = -4
zero of function is when x=0
Step-by-step explanation:
We are given:

Discontinuity of the function occur when the denominator is equal to zero.
So, we need to find the values of x that makes the denominator zero.
The denominator is x^2 - 16
x^2 - 16 =0
x^2 = 16
x = ± 4
So, if the value of x = 4 or value of x=-4 then the function will be discontinuous.
Zero of the function i.e f(x)=0
So, Putting the function equal to zero and finding the value of x

So, zero of function is when x=0
You can take any even number divisible by three and then double it for the denominator
By formula of surface area of cube