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Rainbow [258]
3 years ago
15

given: y = 3x - 4. what is the x-intercept? (0, -4) (0, 4/3) (4/3, 0) user: what is the slope of the line whose equation is y -

2/3 = 0? slope = -2/3 slope = 0 slope = 2/3
Mathematics
2 answers:
aliina [53]3 years ago
8 0
Y = 3x - 4.....x int can be found by subbing in 0 for y and solving for x
0 = 3x - 4
-3x = -4
x = -4/-3
x = 4/3...so the x int = (4/3,0)

y - 2/3x = 0....in y = mx + b form, the m represents the slope. So ur slope is -2/3
Marrrta [24]3 years ago
6 0

Answer with Step-by-step explanation:

y = 3x - 4

The x-intercept is the point where the graph meets the x-axis i.e. the point where y=0

Here the x-intercept is the point such that  3x-4=0

i.e. x=4/3

Hence, x-intercept is: (4/3,0)  

y-2/3x=0

The slope of the line y=mx+c is m

Here, y=2/3x

i.e. m=2/3

Hence, slope of y-2/3x=0 is:

2/3

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Step-by-step explanation:

taking that blank as x

5/2 -x = 1/3

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Bernadette bought two peices of ribbon. One peice is 6 1/4 feet long, and the other is 11 1/2 feet long. Find the total length o
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1. Analyze the following pattern: 1, 2, 5, 10, 17,
valentinak56 [21]

Answer:

n² - 2n + 2

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6 0
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Find a and b if the point p(6,0) and Q(3,2) lie on the graph of ax+ by=12
tiny-mole [99]

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(\stackrel{x_1}{6}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{0}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{6}}}\implies \cfrac{2}{-3}\implies -\cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{2}{3}}(x-\stackrel{x_1}{6})

\stackrel{\textit{multiplying both sides by }\stackrel{LCD}{3}}{3(y-0)~~ = ~~3\left( -\cfrac{2}{3}(x-6) \right)}\implies 3y=-2(x-6) \\\\\\ 3y=-2x+12 \implies \stackrel{a}{2} x+\stackrel{b}{3} y=12

5 0
2 years ago
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