Question

(05.07 MC)

Answer 1

Given that the net of the square pyramid is as shown above, the surface are of the pyramid will be given by:
SA=(number of triangles)*(area of triangle)*(area of square base)
area of one triangle will be:
A=1/2*base*height
A=1/2*0.8*0.75
A=0.3 sq. inches

area of the square base will be:
A=0.75*0.75
A=0.5625
Therefore the surface area will be:
SA=4*0.3*0.5625
SA=0.675 sq. inches