Given that the net of the square pyramid is as shown above, the surface are of the pyramid will be given by: SA=(number of triangles)*(area of triangle)*(area of square base) area of one triangle will be: A=1/2*base*height A=1/2*0.8*0.75 A=0.3 sq. inches
area of the square base will be: A=0.75*0.75 A=0.5625 Therefore the surface area will be: SA=4*0.3*0.5625 SA=0.675 sq. inches
