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2 years ago

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1 answer:

Darina [25.2K]2 years ago

3 0

1. Midpoint = (-2+12)/2 = 10/2 = 5

2. C(5, 2) E(-1, 0) D=?

$x_E= \frac{x_C+x_D}{2} \ \ \ \to \\\\ -1= \frac{5+x_D}{2} \ \ \ \to \ \ \ -2=5+x_D \ \ \to \ \ x_D=-2-5=-7
\\\\\\y_E= \frac{y_C+y_D}{2} \ \ \ \to \\\\ 0= \frac{2+y_D}{2} \ \ \ \to \ \ \ 0=2+y_D \ \ \to \ \ y_D=0-2=-2$

Answer: D(-7, -2)

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9m-m+3=-2(m+1) <br> this thing wants 20 characters so..HI!

MrMuchimi

Answer:

m = -1/2

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Step-by-step explanation:

<u>Step 1: Define</u>

9m - m + 3 = -2(m + 1)

<u>Step 2: Solve for </u><em><u>m</u></em>

Combine like terms: 8m + 3 = -2(m + 1)
Distribute -2: 8m + 3 = -2m - 2
Add 2m on both sides: 10m + 3 = -2
Isolate <em>m</em> term: 10m = -5
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2 years ago

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jolli1 [7]

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2 years ago

The roots of the function f(x) = x2 – 2x – 3 are shown. what is the missing number? x = –1 and x =

andrey2020 [161]

we have

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2 years ago

Read 2 more answers

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sweet-ann [11.9K]

Answer:

x=-2, y=-6

Step-by-step explanation:

Simple substitution.

Since y is isolated in one of the equations already, you can plug it into the second equation.

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Sub. x = -2 into 3x = y:

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2 years ago

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elena55 [62]

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2 years ago