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Mumz [18]
2 years ago
5

I'm thinking of a number. This number is 12 less than its square. What could my number be?

Mathematics
1 answer:
omeli [17]2 years ago
5 0

let nwmber to be X

the number is 12 less than it's square,

so X=12-X^2

=> X^2+X-12=0

=> (X+4)(X-3)=0

=>X= 3, or X=-4

in math we don't usually take negative numbers into account so your number would be 3

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Learning Task 3
ASHA 777 [7]

Answer:

1. The sides are: 38.5, 39.5, 40.5 and 41.5

2. Presently, Inzo is 15 years old and Miz is 10 years old

3. Distance = 3682km

4. Possible pairs are: (12, 14), (16, 18) and (20, 24)

5. L < 38m

Step-by-step explanation:

The question has lots of missing details. See the comment section for complete question

Solving (a):

Given

Shape: Quadrilateral

Sides: Consecutive

Perimeter = 160

Let one of the sides be x. The other sides will be x + 1, x + 2 and x + 3.

So, the perimeter is:

Perimeter = x + x + 1 + x + 2 + x + 3

This gives:

160 = x + x + 1 + x + 2 + x + 3

Collect Like Terms

160 -1-2-3= x+x+x+x

154= 4x

Divide both sides by 4

38.5 = x

x =38.5

<em>So, the sides are: 38.5, 39.5, 40.5 and 41.5</em>

<em></em>

Solving (b):

Given

Presently: Inzo = 10 + Miz

Five years ago: Miz - 5= \frac{1}{3} * (Inzo-5) --- (Missing from the question)

Required: Determine their present ages

Substitute 10 + Miz for Inzo in the second equation

Miz - 5 = \frac{1}{3} * (10 + Miz - 5)

Miz - 5 = \frac{1}{3} * (Miz + 5)

Multiply both sides by 3

3Miz - 15 = Miz + 5

Collect Like Terms

3Miz -Miz = 15  + 5

2Miz= 20

Divide both sides by 2

Miz = 10

Substitute 10 for Miz in Inzo = 10 + Miz

Inzo = 10 + 5

Inzo = 15

<em>So presently, Inzo is 15 years old and Miz is 10 years old</em>

Solving (3):

Given

Express Train:

Speed = 100kph

Time = t

Local Train:

Speed = 45kph

Time = t + 45

Required: Determine the distance between A and B

Distance is calculated as:

Distance = Speed * Time

For the express train:

Distance = 100 * t

For the local train

Distance = 45 * (45 + t)

Distance between both stations are equal; So,

100 * t = 45 * (45 + t)

100 t = 2025 + 45t

Collect Like Terms

100 t -45t= 2025

55t= 2025

Divide by 55

t = 36.82

Substitute 36.82 for t in Distance = 100 * t

Distance = 100 * 36.82

Distance = 3682km

Solving (4):

Let the even numbers be: n and n + 2.

Sum greater than 24: n + n + 2 > 24

Sum less than 60: n + n + 2 < 60

So, we have:

n + n + 2 > 24

2n + 2 > 24

Collect Like Terms

2n > 24-2

2n > 22

n > 11

n + n + 2 < 60

2n + 2< 60

Collect Like Terms

2n < 60-2

2n < 58

Divide by 2

n

So, we have:

n > 11 and n < 29

So, possible pairs are: (12, 14), (16, 18) and (20, 24)

Solving (5):

Given

Perimeter < 152m

Required: Find the possible lengths

Let the length be L.

Perimeter is calculated as:

Perimeter =4 * L

Perimeter =4  L

So, we have:

4L < 152m

Divide through by 4

L < 38m

Hence, length is less than 38m (e.g. 37m)

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Answer:

Step-by-step explanation:

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Answer:

x = 34

Step-by-step explanation:

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Find the area of a rectangle that has a length of 12 m and a width of 7 m
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