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frutty [35]
3 years ago
6

A race car accelerates at 2 m/s2 from 12 m/s to 18 m/s. Find distance and time

Mathematics
1 answer:
Marizza181 [45]3 years ago
6 0

Answer:

Distance = 45 meters

Time = 3 seconds

Step-by-step explanation:

Here, we want to calculate distance and time

To find the time, we can use one of the Newtons law of motion

V = U + at

In this question

V = final velocity = 18 m/s

U = initial velocity = 12 m/s

a = acceleration

Thus;

18 = 12 + 2(t)

18-12 = 2t

2t = 6

t = 6/2

t = 3 seconds

Mathematically we can also find the distance using one of the equation of motion;

D = ut + 1/2 at^2

D = 12(3) + 1/2 * (2) * 3^2

D = 36 + 9

D = 45 m

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SU and VT are chords that intersect at point R.
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Answer:

<h2>The length of the line segment VT is 13 units.</h2>

Step-by-step explanation:

We know that SU and VT are chords. If the intersect at point R, we can define the following proportion

\frac{RS}{RT} =\frac{RV}{RU}

Where

RS=SR=x+6\\RT=x+4\\VR=RV=x+1\\RU=x

Replacing all these expressions, we have

\frac{x+6}{x+4} =\frac{x+1}{x}

Solving for x, we have

x(x+6)=(x+4)(x+1)\\x^{2} +6x=x^{2} +x+4x+4\\6x-5x=4\\x=4

Now, notice that chord VT is form by the sum of RT and RV, so

VT=VR+RT\\VT=x+1+x+4\\VT=2x+5

Replacing the value of the variable

VT=2(4)+5\\VT=8+5\\VT=13

Therefore, the length of the line segment VT is 13 units.

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3 years ago
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3 years ago
I tried 8 and 1 and this is probably and easy question but can you pls help
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Answer:

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Answer:

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