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poizon [28]
3 years ago
9

Reflect shape A in the line x=-1

Mathematics
2 answers:
natulia [17]3 years ago
4 0

Answer:

Step-by-step explanation:

Hey! I cant draw the shape in the answer box. Sowiee

Nataly [62]3 years ago
4 0

Coordinates for the shape:

(-3,-2), (-5,-2), (-5,-3), (-4,-3), (-4,-4), (-3,-4)

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A scuba diver starts at 85 3/4 meters below the surface of the water and descends until he reaches 103 1/5
RSB [31]

Answer:

From his starting point of 85 3/4, he descended 17 9/20 meters

Step-by-step explanation:

We want to know how much farther he went down from his starting point.

103 1/5 - 85 3/4

S

tart off by making the denominators of both the numbers the same.

103 1/5 - 85 3/4

103 4/20 - 85 15/20

Make them into improper fractions

2064/20 - 1715/20 = 349/20

Make 349/20 into a mixed fraction

17 9/20

5 0
2 years ago
In order to tell if a graph is a function it must
nikitadnepr [17]
You can use the vertical line test (the blue lines on the drawing) and if the other end or if any part of the line touches the blue line, then it isn’t a function.

5 0
2 years ago
Suppose triangle ABC will be dilated using the rule . What will be the distance from the center of dilation, Q, to the image of
Blababa [14]

Answer:

4

Step-by-step explanation:

The rule of dilation is D_{Q,\frac{2}{3}}. This means that each distance QX' is equal to \dfrac{2}{3}QX, where X is initial point and X' is its image after dilation.

Since QA=6, then

QA'=\dfrac{2}{3}\cdot 6=4.

6 0
3 years ago
Read 2 more answers
TIME REMAINING
ollegr [7]

Answer:

  (b)  (x -10)(x +10)

Step-by-step explanation:

The factorization of the difference of squares is a special form:

  a² -b² = (a -b)(a +b)

<h3>Application</h3>

Your expression is recognizable as the difference of squares:

  x² -100 = x -10²

Using the above form, the factorization is ...

  = (x -10)(x +10) . . . . . . . . matches the second choice

7 0
2 years ago
Find the greatest common factor of each set of numbers 12 54
max2010maxim [7]
I hope this helps you

4 0
3 years ago
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