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3 years ago

Which two values of x are roots of the polynomial below? x^2 + 5x + 9

2 answers:

8 0

They are not real.
b^2 - 4ac =
b = 5
a = 1
c = 9
5^2 - 4(1)(9)
25 - 36
- 11
The quadratic formula is
x = (- b) +/- sqrt(b^2 - 4ac)
. . . . .==============
. . . . . . . . . . 2(a)
x = ( (- 5 +/- sqrt(-11) ) / 2
x = ( - 2.5 +/- sqrt(11) i / 2

4vir4ik [10]3 years ago

5 0

$x^2+5x+9$

The polynomial cannot be factored with rational numbers due to b being 5. You can factor it if b is equal to 6.

None

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Find the constant of variation for the relation and use it to write an equation for the statement. Then solve the equation

Olenka [21]

Answer:

y = $\frac{49}{3}$

Step-by-step explanation:

Given that y varies directly as x then the equation relating them is

y = kx ← k is the constant of variation

To find k use the condition y = 7 when x = 3

k = $\frac{y}{x}$ = $\frac{7}{3}$ , thus

y = $\frac{7}{3}$ x ← equation of variation

When x = 7, then

y = $\frac{7}{3}$ × 7 = $\frac{49}{3}$

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3 years ago

What's the perimeter?

zavuch27 [327]

Answer: D. 56 Units?

Explanation:
Side 1 - 9
Side 2 - 4
Side 3 - 4
Side 4 - 8
Side 5 - 11
Side 6 - 3
Side 7 - 2
Side 8 - 15

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5 0

2 years ago

Read 2 more answers

How do you factor this?

lubasha [3.4K]

Answer:

Step-by-step explanation:

What two numbers multiply to equal -48, but add to equal -2? The method is multiplying a*c and seeing if they add up to b. Those two numbers are -8 and +6.

$6x^2-2x-8=6x^2-8x+6x-8$

Now, factor by grouping

$(6x^2-8x)+(6x-8)=2x(3x-4)+2(3x-4)\\(2x+2)(3x-4)$

3 0

2 years ago

E temperature t of a metal sphere is inversely proportional to the distance from the centre of the sphere (the origin (0, 0, 0))

olasank [31]

(-x, -y, -z) the vector form (x, y, z) to the origin, in the direction of the greatest increase.

<h3>How to calculate temperature?</h3>

The quantity or amount of radiation contained in material or item, as measured by a temperature or sensed by touch and stated on a numerical scale.

The temperature T of a ball bearing is inverse to the length first from the origin, which we consider to be the center of the ball. The temperature at the exact location

(x, y, z) is a point on the sphere, the temperature at this point is given by

$T(x,y,z)= \dfrac{k}{(x^2 +y^2+z^2)^{1/2}}$

Where k is constant, then we have

T(1, 2, 2) = k/3 = 170

k = 510

$T(x,y,z)= \dfrac{510}{(x^2 +y^2+z^2)^{1/2}}$

Then we have

$\rm \triangledown T = \left ( -\dfrac{510x}{(x^2 +y^2+z^2)^{1/2}}, -\dfrac{510y}{(x^2 +y^2+z^2)^{1/2}}, \dfrac{510z}{(x^2 +y^2+z^2)^{1/2}} \right )\\\\\\\triangledown T (1, 2, 2) = -\dfrac{510}{27} (1, 2, 2) =-\dfrac{170}{9} (1, 2, 2)$

Then the direction will be from (1, 2, 2) to (4, 3, 5) will be (3, 1, 3)

So u = (3/√19, 1/√19, 3/√19)

Then we get

$\rm \triangledown T \cdot u = \dfrac{-170}{9}(1, 2, 2) \cdot \left (\dfrac{3}{\sqrt{19}}, \dfrac{1}{\sqrt{19}}, \dfrac{3}{\sqrt{19}} \right )\\\\\\\triangledown T \cdot u = - \dfrac{170}{9\sqrt{19}} (3 + 2 + 6)\\\\\\\triangledown T \cdot u = -\dfrac{1870}{9\sqrt{19}}$

The direction of the greatest inverse in the temperature is given by any vector parallel to and having the same direction $\triangledown$ T. (-x, -y, -z) the vector form (x, y, z) to the origin, in the direction of the greatest increase.