Answer:
10/12x100%= 83.3%
Step-by-step explanation:
Length = 2W
P= 2L + 2W
60 = 2(2W) + 2W
60= 4W +2W
60 = 6W
60/6W = 6W/6W
w = 10
Length = 2(10)
Length = 20
P= 2L + 2W
60= 2(20) + 2(10)
60= 40 +20
60 = 60
Given that
The cost of 1 m ribbon = Rs.75
The cost of 7/5 m ribbon
→ (7/5)×75
→ (7×75)/5
→7×15
→₹ 105
The cost of 7/5 m ribbon is ₹105.
Answer to the question is..
32,34,36
largest is 36
The required probability is 
<u>Solution:</u>
Given, a shipment of 11 printers contains 2 that are defective.
We have to find the probability that a sample of size 2, drawn from the 11, will not contain a defective printer.
Now, we know that, 
Probability for first draw to be non-defective 
(total printers = 11; total defective printers = 2)
Probability for second draw to be non defective 
(printers after first slot = 10; total defective printers = 2)
Then, total probability 