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Y_Kistochka [10]
3 years ago
7

Confused on the second part

Mathematics
1 answer:
marin [14]3 years ago
4 0

That I remember the answer would be a^n over 1

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Prove that 7-4√7 is irrational​
mixas84 [53]

Answer:

hey ;

7 - 4 \sqrt{7}

is an irrational number

Step-by-step explanation:

here's the proof in attachment.

<em>i</em><em> </em><em>hope</em><em> </em><em>it</em><em> </em><em>helped</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

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X -5x -14=0 quadratic formula
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No its a negitive number one x minus five x's equal -14
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Please help <br> Algebra 1<br> Look at the photo below...
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3 years ago
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7 0
3 years ago
Finish the steps below to write a quadratic function for the parabola shown. Use the vertex form, f(x) = a(x – h)2 + k, and subs
Marta_Voda [28]
We have

f(x) = a(x – h)²<span> + k
 we know the vertex v(5,3)
</span><span>substitute in the values for h and k
</span>f(x) = a(x – 5)²<span> + 3 
</span><span>Use another point and substitute in values for x and f(x). 
for the point (6,5)
</span><span>Solve for a.
5 = a(6 – 5)2 + 3-------------- > 5=a+3-------------> a=2
</span>
The function is f(x)=a(x – h)2 + k-------- > 2(x – 5)² + 3
f(x)= 2(x – 5)² + 3-------- > 2[x²-10x+25]+3=2x²-20x+50+3=2x²-20x+53
f(x)=2x²-20x+53
<span>
the answer is f(x)=</span> 2(x – 5)² + 3----------------- > (f(x)=2x²-20x+53)<span>

</span>
8 0
3 years ago
Read 2 more answers
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