All categories

2 years ago

How do you round 11,540 to two decimal palces

1 answer:

4 0

Ok to find this we have to divide 12,000/5770 to find the number of half lives

we get 2.07972270364

we can round this decimal to 3

3 half lives

You might be interested in

If Rachel can read 10 pages in 12 minutes how long does it take her to read 8 pages

juin [17]

Answer:

9.6

Step-by-step explanation:

Step 1:

Find the rate of proportion

We can do 12/10 to find how many minutes it takes her to read 1 page, or 1.2.

Step 2:

Multiply 1.2 by 8 to get 9.6

ALTERNATIVE METHOD:

Divide 10 by 8 to get 1.25. Then divide 12 by 1.25 to get 9.6

4 0

2 years ago

Plz answer I need a lot of help as soon as possible.

Maru [420]

Answer:

your answer is a i think sorry if im wrong

Step-by-step explanation:

3 0

2 years ago

PLZ HELP IM IN 8TH GRADE

jok3333 [9.3K]

Answer:

recently. The dollar amount collected was $835. Adult tickets, A sold for $8 each and childrens tickets, C sold - 119… ... Adult tickets, A sold for $8 each and childrens tickets, C sold for $5 each. Write a system of ... Now, we need to know how many tickets were sold from both adults and children. Our new ...

1 answer

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

I can't figure out how to do (i + j) x (i x j)for vector calc

Vinil7 [7]

In three dimensions, the cross product of two vectors is defined as shown below

$\begin{gathered} \vec{A}=a_1\hat{i}+a_2\hat{j}+a_3\hat{k} \\ \vec{B}=b_1\hat{i}+b_2\hat{j}+b_3\hat{k} \\ \Rightarrow\vec{A}\times\vec{B}=\det (\begin{bmatrix}{\hat{i}} & {\hat{j}} & {\hat{k}} \\ {a_1} & {a_2} & {a_3} \\ {b_1} & {b_2} & {b_3}\end{bmatrix}) \end{gathered}$

Then, solving the determinant

$\Rightarrow\vec{A}\times\vec{B}=(a_2b_3-b_2a_3)\hat{i}+(b_1a_3+a_1b_3)\hat{j}+(a_1b_2-b_1a_2)\hat{k}$

In our case,

$\begin{gathered} (\hat{i}+\hat{j})=1\hat{i}+1\hat{j}+0\hat{k} \\ \text{and} \\ (\hat{i}\times\hat{j})=(1,0,0)\times(0,1,0)=(0)\hat{i}+(0)\hat{j}+(1-0)\hat{k}=\hat{k} \\ \Rightarrow(\hat{i}\times\hat{j})=\hat{k} \end{gathered}$

Where we used the formula for AxB to calculate ixj.

Finally,

$\begin{gathered} (\hat{i}+\hat{j})\times(\hat{i}\times\hat{j})=(1,1,0)\times(0,0,1) \\ =(1\cdot1-0\cdot0)\hat{i}+(0\cdot0-1\cdot1)\hat{j}+(1\cdot0-0\cdot1)\hat{k} \\ \Rightarrow(\hat{i}+\hat{j})\times(\hat{i}\times\hat{j})=1\hat{i}-1\hat{j} \\ \Rightarrow(\hat{i}+\hat{j})\times(\hat{i}\times\hat{j})=\hat{i}-\hat{j} \end{gathered}$

Thus, (i+j)x(ixj)=i-j

8 0

1 year ago

Simplify: (2x²y²) (-3xy³) please no links and explain please. I need it fast

Shtirlitz [24]

Step-by-step explanation:

Solution:

(6xy) × (-3x²y³)

= {6 × (-3)} × {xy × x²y³}

= -18x1+2 y1+3

= -18x³y⁴.

3 0

2 years ago