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Korvikt [17]
2 years ago
11

The population of a town,

Mathematics
1 answer:
kicyunya [14]2 years ago
8 0

Answer:

hi

Step-by-step explanation:

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Need help asap pls ​
irakobra [83]

Answer:

the answare is infinty

Step-by-step explanation:

5 0
3 years ago
Round to nearest thousand then subtract
Helga [31]

Answer:

3000

Step-by-step explanation:

5,503 - 3417

6000 - 3000

3000

5 0
3 years ago
-1/4×3/5×-2/5 what dose this Equal
Alex787 [66]

Answer:

3/50

Step-by-step explanation:

Multiply across the fraction- First start with the numerator digits (-1, 3, and -2)

-2*-1= 2 and 2*3= 6 So you should have 6 as your numerator

Now look at the denominator digits (4, 5, and 5)

Multiply across and you should get 100 as your denominator

You now have 6/100 but you are not done yet! Don't forget to simplify the fraction to get your final answer

Both 6 and 100 are divisible by 2 (6 divided by two is 3, and 100 divided by two is 50)

Thus, your final answer should be 3/50!

7 0
3 years ago
Simplify the linear expression. ​
Hunter-Best [27]

Answer:

5a/3+1/8-a/6-1/2

Step-by-step explanation:

4 0
2 years ago
What would be the solution to this Pythagorean/Trigonometric equation? (csc² A - 1) sen² A = cos² A
Anna007 [38]

Answer:

(csc^2 A -1) sin^2 A = cos^2 A

We know that csc x= \frac{1}{sin x} and using this identity we have:

\frac{sin^2 A}{sin^2 A} - sin^2 A = cos^2 A

1 = cos^2 A + sin^2 A

And if we remember the equation above represent the fundamental identity in trigonometry and is satisfied for every real number and we can say that the solution for this case is:

A= [X | x \in R]

Step-by-step explanation:

For this case we have the following equation given:

(csc^2 A -1) sin^2 A = cos^2 A

We know that csc x= \frac{1}{sin x} and using this identity we have:

\frac{sin^2 A}{sin^2 A} - sin^2 A = cos^2 A

1 = cos^2 A + sin^2 A

And if we remember the equation above represent the fundamental identity in trigonometry and is satisfied for every real number and we can say that the solution for this case is:

A= [X | x \in R]

8 0
3 years ago
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