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Salsk061 [2.6K]
3 years ago
14

A used car dealership categorizes its salespeople by the number of cars sold per year, with the categories being 0-8, 9-16, 17-2

4, and 25 or more. if the following data represents the numbers of cars sold by its salespeople last year, how many salespeople were in the 17-24 category?
Mathematics
2 answers:
Y_Kistochka [10]3 years ago
5 0

Answer:

B.1

Step-by-step explanation:

apexs

OlgaM077 [116]3 years ago
4 0
The correct answer for the question that is being presented above is this one: "<span>C. 1." </span>if the <span>following data represents the numbers of cars sold by its salespeople last year, there is only 1 salespeople were in the 17-24 category</span>
Additional Information: <span>2, 31, 29, 5, 14, 7, 10, 25, 3, 22

Here are the following choices:
A. 2
B. 3
C. 1
D. 4</span>
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Solve for x, y, and z. <br> y=1/2z<br> x+2y+5z=2<br> 3x+6y-3z=9
Contact [7]
Rearrange the equation,

0x + y - ½z = 0 ==> Equation 1
x + 2y + 5z = 2 ==> Equation 2
3x + 6y - 3z = 9 ==> Equation 3

Put the 3 equation in matrix form,

0\ \ \ \ \ 1\ \ -{\frac{1}{2} }\ \ \ \ \ \ \ \ 0 \\ 1\ \ \ \ \ 2\ \ \ \ \ \ \ 5\ \ =\ 2 \\ 3\ \ \ \ \ 6\ \ -3\ \ \ \ \ \ \ \ \ 9

Find the determinant, D, of the matrix,

0\ \ \ \ \ 1\ \ -{\frac{1}{2} } \\ 1\ \ \ \ \ 2\ \ \ \ \ \ \ 5\ = \ D \\ 3\ \ \ \ \ 6\ \ -3

By Sarrus' rule,
D = [(0 × 2 × -3) + (1 × 5 × 3) + (-½ × 1 × 6)] - [(-½ × 2 × 3) + (5 × 6 × 0) + (-3 × 1 × 1)]
D = [0 + 15 + (-3)] - [(-3) + 0 + (-3)]
D = 12 + 6
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By cramer's rule,

x = Determinant of x ÷ D
Let determinant of x = Dx,

0\ \ \ \ \ 1\ \ -{\frac{1}{2} } \\ 2\ \ \ \ \ 2\ \ \ \ \ \ \ 5\ = \ Dx \\ 9\ \ \ \ \ 6\ \ -3
To get this determinant, substitude 0, 2 and 9 with the unknown you're finding, in this case, x.

By Sarrus' rule,
Dx = [(0 × 2 × -3) + (1 × 5 × 9) + (-½ × 2 × 6)] - [(-½ × 2 × 9) + (0 × 5 × 6) + (-3 × 1 × 2)]
Dx = [0 + 45 + (-6)] - [-9 + 0 + (-6)]
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x = Dx ÷ D
x = 54 ÷ 18
x = 3

By cramer's rule,

y = Determinant of y ÷ D
Let determinant of y = Dy

0\ \ \ \ \ 0\ \ -{\frac{1}{2} } \\ 1\ \ \ \ \ 2\ \ \ \ \ \ \ 5\ = \ Dy \\ 3\ \ \ \ \ 9\ \ -3

By Sarrus' rule,
Dy = [(0 × 2 × -3) + (0 × 5 × 3) + (-½ × 1 × 9)] - [(-½ × 2 × 3) + (5 × 9 × 0) + (-3 × 0 × 1)
Dy = [0 + 0 - 4½] - [-3 + 0 + 0]
Dy = -4½ + 3
Dy = -1½

y = Dy ÷ D
y = -1½ ÷ 18
y ≈ 0.0833 (3 significant figure)

Solving z using equation rule,
y = ½z
0.0833 = ½z
z = 0.0833 ÷ ½
z ≈ 0.167 (3 significant figure)

∴ x = 3, y = 0.0833 and z = 0.167.
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Answer:

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