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3 years ago

Mt Whitney in California is 14,494 feet tall Denali in Alaska is 5,826 feet taller than my Whitney how tall is Denali

Mathematics

2 answers:

snow_tiger [21]3 years ago

7 0

20,320 feet hope this helps you out. Enjoy :)

aniked [119]3 years ago

3 0

Mt Denali is 20,310 ft. tall. However with the numbers in your equation it omes out to be 20,320 ft tall. You might try both.

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Y=x+2 2x-y=-4 Solve the systems of equations

larisa86 [58]

Answer:

Step-by-step explanation:

Given that,

y=x+2 equation 1

2x-y=-4 equation 2

This is a simultaneous equation.

Substitute equation 1 into equation 2

2x-y=-4. Since y=x+2

2x-(x+2) = -4

2x-x-2 = -4

x-2 = -4

x = -4+2

x = -2

Also from equation 1

y=x+2

Since x=-2

y=-2+2

y=0

Then, solution (x, y) = (-2,0)

4 0

3 years ago

Read 2 more answers

The Sky Ranch is a supplier of aircraft parts. Included in stock are 6 altimeters that are correctly calibrated and two that are

almond37 [142]

Answer:

For x = 0, P(x = 0) = 0.35

For x = 1, P(x = 1) = 0.54

For x = 2, P(x = 2) = 0.11

For x = 3, P(x = 3) = 0

Step-by-step explanation:

We are given that the Sky Ranch is a supplier of aircraft parts. Included in stock are 6 altimeters that are correctly calibrated and two that are not. Three altimeters are randomly selected, one at a time, without replacement.

Let X = the number that are not correctly calibrated.

Number of altimeters that are correctly calibrated = 6

Number of altimeters that are not correctly calibrated = 2

Total number of altimeters = 6 + 2 = 8

(a) For x = 0: means there are 0 altimeters that are not correctly calibrated.

This means that all three selected altimeters are correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = $^{8}C_3$

The number of ways of selecting 3 altimeters from a total of 6 altimeters that are correctly calibrated = $^{6}C_3$

So, the required probability = $\frac{^{6}C_3}{^{8}C_3}$

= $\frac{20}{56}$ = 0.35

(b) For x = 1: means there is 1 altimeter that is not correctly calibrated.

This means that from three selected altimeters; 1 is not correctly calibrated and 2 are correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = $^{8}C_3$

The number of ways of selecting 2 correctly calibrated altimeters from a total of 6 altimeters that are correctly calibrated = $^{6}C_2$

The number of ways of selecting 1 not correctly calibrated altimeters from a total of 2 altimeters that are not correctly calibrated = $^{2}C_1$

So, the required probability = $\frac{^{6}C_2 \times ^{2}C_1 }{^{8}C_3}$

= $\frac{30}{56}$ = 0.54

(c) For x = 2: means there is 2 altimeter that is not correctly calibrated.

This means that from three selected altimeters; 2 are not correctly calibrated and 1 is correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = $^{8}C_3$

The number of ways of selecting 1 correctly calibrated altimeters from a total of 6 altimeters that are correctly calibrated = $^{6}C_1$

The number of ways of selecting 2 not correctly calibrated altimeters from a total of 2 altimeters that are not correctly calibrated = $^{2}C_2$

So, the required probability = $\frac{^{6}C_1 \times ^{2}C_2 }{^{8}C_3}$

= $\frac{6}{56}$ = 0.11

(d) For x = 3: means there is 3 altimeter that is not correctly calibrated.

This case is not possible, so this probability is 0.

6 0

3 years ago

Divide x^4+3x^3-2x^2+4 by x-2 what is the correct synthetic division and quotinent

frez [133]

Answer:

Step-by-step explanation:

The correct divisor is 2. You change the sign of the real number without a variable when that real number is the divisor.

So - 2 becomes 2 and C and D are both incorrect.

The 0 comes between - 2 and 4 because the x term is 0x. (there isn't one).

That makes B wrong.

The answer is A

3 0

3 years ago

Point Q was rotated by -150° (the center of rotation is indicated).

DedPeter [7]

Answer:It’s A

Step-by-step explanation: the reason being is look from the origin(0,0) to the blue dot there is a circle of you think about try to imagine that circle crossing the whole place it couldn’t be C or D because that’s less than the imaginary circle and also 150 is close to 180. 180 is fully behind and A is close to 180 than B. Also remember, negative degrees is only clockwise and positive degrees are COUNTER. Hope it helps especially on the exam it also took me a bit to understand but it makes sense now.

4 0

3 years ago

The sum of the radius of the base and the height of a solid cylinder is 37m. If the total surface area of the cylinder is 1628 m

MA_775_DIABLO [31]

Answer:

4618.14 $m^{3}$ or 4618 $m^{3}$