Answer: r = -11, q =3.5
Step-by-step explanation:
4q – 2r = 36 ....... eqn. 1
6q + r = 10 ..............eqn 2.
from eqn. 2 make r subject formula i.e.
r = 10- 6q (substitute for 'r' in eqn. 1)
we have;
4q - 2(10-6q) = 36 (open bracket)
4q -20 + 12q = 36 (collect like terms)
4q+12q = 36+20
16q = 56
q = 56/16
q = 3.5
substitute for q in eqn. 2.......
6(3.5) + r = 10
21 + r = 10
r = 10-21
r = -11, q =3.5
Please give me brainliest...thanks
Answer: y = - 6x + 2
Step-by-step explanation:
The equation of a straight line can be represented in the slope intercept form as
y = mx + c
Where
m = slope = (change in the value of y in the y axis) / (change in the value of x in the x axis)
The equation of the given line is
4y + 24x = 32
Rearranging it so that it will take the slope intercept form, it becomes
4y = - 24x + 32
Dividing through by 4, it becomes
y = - 6x + 8
Comparing with the slope intercept form, slope = - 6
If two lines are parallel, it means that they have the same slope. Therefore, the slope of the line passing through (1,-4) is - 6
To determine the intercept, we would substitute m = - 6, x = 1 and y = -4 into y = mx + c. It becomes
- 4 = - 6 × 1 + c = - 6 + c
c = - 4 + 6 = 2
The equation becomes
y = - 6x + 2
Answer: 31, hope this helps❤
Step-by-step explanation:
Answer: The area of Charlene's rhombus is nine times smaller than the area of Jerry's rhombus.
Step-by-step explanation:
I will assume that the exercise says "
times the base and height of Jerry’s rhombus".
The area of a rhombus can be calculated with the following formula:

Where "b" is the length of the base and "a" is the altitude or the height.
Then, you can calculate the area using the formula shown above.
Therefore, you get:
1. Jerry's rhombus:

2. Charlene's rhombus:

Dividing the area calculated, you get:

Therefore, you can conclude that the area of Charlene's rhombus is nine times smaller than the area of Jerry's rhombus.