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kenny6666 [7]
3 years ago
14

Which expression has the same value as 59.2 - 84.7

Mathematics
1 answer:
yawa3891 [41]3 years ago
5 0
Which expression has the same value as 59.2 - 84.7

-84.7 + 59.2
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HELP!!!! I WILL MARK YOU BRAINLIST
Marina86 [1]

Answer:

k= 12 x= 5

Step-by-step explanation:

4 0
3 years ago
Evaluate aa when a equals -2.<br><br> 1)-4<br> 2)4<br> 3)1/4<br> 4)-1/4
Sav [38]
A= -2
aa= -2(-2)= 4
Hence, the correct answer is the second option, 4.
5 0
3 years ago
Read 2 more answers
Solve the equation<br>12E − 4 = 0
Scorpion4ik [409]
This could get complicated.  Please try to follow my steps carefully:

Begin by writing the equation to be solved:    <u>12E - 4 = 0</u>

Add 4 to each side of the equation:  12E = 4

Divide each side by 12:                      E = 4/12 = 1/3 .
7 0
3 years ago
A random telephone survey of 1021 adults (aged 18 and older) was conducted by Opinion Research Corporation on behalf of Complete
Wewaii [24]

Answer:

a. See attachment below

b. 613 people

c. Categorical

Step-by-step explanation:

a. View attachment below

b.

Given

Total Number of People Surveyed = 1021

X tax return by professional / Number of People Surveyed = 60%

X tax /1021 = 0.6

X tax = 0.6 * 1021

X tax = 612.6

X tax = 613------ Approximated

So, the number of people used an accountant or professional tax preparer are 613.

c.

The data for preparing a tax return will be considered as categorical as the methods for a person to file his/her tax returns are categorized into four which are:

1.Electronically

2.Manual preparation

3.Online tax service

4.Use of software tax program

7 0
3 years ago
Find the minimum and maximum of f(x,y,z)=x^2+y^2+z^2 subject to two constraints, x+2y+z=4 and x-y=8.
Alika [10]
The Lagrangian for this function and the given constraints is

L(x,y,z,\lambda_1,\lambda_2)=x^2+y^2+z^2+\lambda_1(x+2y+z-4)+\lambda_2(x-y-8)

which has partial derivatives (set equal to 0) satisfying

\begin{cases}L_x=2x+\lambda_1+\lambda_2=0\\L_y=2y+2\lambda_1-\lambda_2=0\\L_z=2z+\lambda_1=0\\L_{\lambda_1}=x+2y+z-4=0\\L_{\lambda_2}=x-y-8=0\end{cases}

This is a fairly standard linear system. Solving yields Lagrange multipliers of \lambda_1=-\dfrac{32}{11} and \lambda_2=-\dfrac{104}{11}, and at the same time we find only one critical point at (x,y,z)=\left(\dfrac{68}{11},-\dfrac{20}{11},\dfrac{16}{11}\right).

Check the Hessian for f(x,y,z), given by

\mathbf H(x,y,z)=\begin{bmatrix}f_{xx}&f_{xy}&f_{xz}\\f_{yx}&f_{yy}&f_{yz}\\f_{zx}&f_{zy}&f_{zz}\end{bmatrix}=\begin{bmatrix}=\begin{bmatrix}2&0&0\\0&2&0\\0&0&2\end{bmatrix}

\mathbf H is positive definite, since \mathbf v^\top\mathbf{Hv}>0 for any vector \mathbf v=\begin{bmatrix}x&y&z\end{bmatrix}^\top, which means f(x,y,z)=x^2+y^2+z^2 attains a minimum value of \dfrac{480}{11} at \left(\dfrac{68}{11},-\dfrac{20}{11},\dfrac{16}{11}\right). There is no maximum over the given constraints.
7 0
3 years ago
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