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4 years ago

Triangle pqr is a right triangle. what is the best approximation of the length of segment pq? (Note:tan76°)

Mathematics

1 answer:

andrew11 [14]4 years ago

4 0

Answer:

PQ = 16.04cm

Step-by-step explanation:

θ = 76°

QR = 4cm

PQ = ?

Since it's a right angle triangle,

QR = adjacent

PQ = opposite

Tanθ = opposite/adjacent

Tan76 = pq / 4

PQ = 4tan76

PQ = 4 * 4.010

PQ = 16.04cm

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Answer:

86.5

$14 + 8 + 12.5 = 34.5 \: \: 121 - 34.5 = 86.5$

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3 years ago

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3 years ago

the bus bound for northtown departs every 15 minutes and the bus for eastown departs every 18 minutes from the central station.

USPshnik [31]

Considering the least common factor of 15 and 18, it is found that they will depart from the central station at the same time at 11 AM.

<h3>How to find the time it takes for periodic events to repeat at the same time?</h3>

To find the time that passes between the events happening at the same time, we need to find the least common multiple of the periods.

In this problem, the periods are of 15 and 18, hence their lcm is found as follows:

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Hence:

lcm(15,18) = 2 x 3 x 3 x 5 = 90 minutes.

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More can be learned about the least common factor at brainly.com/question/16314496

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2 years ago

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Gre4nikov [31]

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4 years ago

A jar contains 6 blue, 4 red, and 2 green marbles. What is the probability that three blue marbles are drawn with out replacemen

ch4aika [34]

Answer: The required probability is 9.09%.

Step-by-step explanation: Given that a jar contains 6 blue, 4 red, and 2 green marbles.

We are to find the probability that three blue marbles are drawn with out replacement.

Total number of marbles = 6 + 4 + 2 = 12.

After drawing one blue marble, we are left with total 11 marbles. And after drawing the second blue marble, we are left with total 10 marbles.

Therefore, the probability of drawing three blue marbles without replacement is given by

$p\\\\\\=\dfrac{^6C_1}{^{12}C_1}\times\dfrac{5C_1}{^{11}C_1}\times\dfrac{^4C_1}{^{10}C_1}\\\\\\=\dfrac{6}{12}\times\dfrac{5}{11}\times\dfrac{4}{10}\\\\\\=\dfrac{1}{11}\\\\\\=\dfrac{1}{11}\times100\%\\\\=9.09\%.$

Thus, the required probability is 9.09%.

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4 years ago