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shtirl [24]
4 years ago
5

Help mee plezzzzzzzzzzzzzzzzzzz

Mathematics
2 answers:
Gnesinka [82]4 years ago
8 0

Answer:

-81

Step-by-step explanation:

GalinKa [24]4 years ago
7 0
9:(9+-10)x9
= 9:-1x9
-9x9
= -81
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What is the solution to 2x+y=1 and x-2y=3
Masteriza [31]

Answer:

Step-by-step explanation:

2x+y=1---------> y=-2x+1

x-2y=3

2) x-2(-2x+1)=3                          

x+4x-2=3

5x=5

x=1

3) 2x+y=1 when x=1

2(1)+y=1

2+y=1

y=1

the answer is (1,1)

5 0
3 years ago
Please HELP NEEDED ASAP APPRECIATED !! Brainlestwill be given
ryzh [129]
I think you were given (sqrt(x))^5 
sqrt(x) = x^(1/2) so 
(x^(1/2) )^5 = x^(5/2)
The answer closest to the bottom of the page <<<<===== answer.


4 0
3 years ago
The number can be divided by the least common multiple of 3 and 5
kondaur [170]

9514 1404 393

Answer:

  255

Step-by-step explanation:

If the sum of digits is 12, the number is divisible by 3. If the number ends in 0 or 5, it is divisible by 5. So, we're looking for ...

  2x0 . . . where x is a digit and 2+x+0 = 12 . . . . . . not possible

  2x5 . . . where x is a digit and 2+x+5 = 12 . . . . true for x=5

The number is 255.

3 0
3 years ago
128= 4^2x times 2^x <br> What is x?
algol [13]

Answer:

x=7/5

Step-by-step explanation:

We can write it in exponential form

128= 2^2*2x * 2^x

2^4x+x=5x

2^5x=128

2^5x=2^7

5x=7

x=7/5

3 0
3 years ago
Solve for x:<br> x^2=a<br><br> If a&lt;0, then <br> If a=0, then<br> If a&gt;0, then
Anastaziya [24]

if a > 0, there are two possible solutions:

x^{2} = a\\\sqrt{x^{2} } = \sqrt{a} \\

the square root of a square is the base in absolute value bars

|x| = \sqrt{a}

x = -\sqrt{a} ; x = \sqrt{a}

if a = 0, that means x = 0. anything multiplied by 0 is 0

if a < 0, there are no solutions because anything squared has to be positive

6 0
3 years ago
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