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alexandr1967 [171]

3 years ago

15

Travis has 3 months to save money for a trip. An airplane ticket costs more than $300. If he saves the same amount of money, a,

each month, how much does he need to save each month to pay for the ticket?

1 answer:

olganol [36]3 years ago

3 0

Answer:

$100

Step-by-step explanation:

300 divided by 3= 100

He needs to save $100 each month.

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Find the area of a sector with a central angle of 120° and a diameter of 7.3 cm. Round to the nearest tenth.

Andru [333]

Answer: $14cm^{2}$

Step-by-step explanation:

diameter=7.3cm

radius= $\frac{diameter}{2}$

= $\frac{7.3}{2}$

=3.65cm

angle =120°

area= $\frac{angle (tita)}{360}$ × $\frac{\pi r^{2} }{1}$

= $\frac{120}{360}$ × $\frac{22}{7}$ × $3.65^{2}$

= $13.95cm^{2}$

≅ $14cm^{2}$

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Step-by-step explanation:and for the other one I don’t know but ima try it should be two because 2x2=4 and so y=1-2x2-4 that’s what I think sorry. I got it wrong and do good on your test for me please

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2 years ago

XYZ Toys makes a ec 4- Me Baby Doll for $10.40. They mark up the cost by 55%. What is the selling price for the Feed-Me Baby Dol

vladimir1956 [14]

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3 years ago

Read 2 more answers

If a fire is burning a building and it takes 2 hours to put it out using 2000 gal./min., what minimum diameter cylindrical tank

strojnjashka [21]

Answer:

The minimum diameter of the cylindrical tank needed to store the quantity needed to put out the fire is approximately 58.415 feet.

Step-by-step explanation:

A gallon equals 0.134 cubic feet. First, we determine the amount of water ( $Q$ ), measured in cubic feet, needed to put out the fire under the assumption that water is consumed at constant rate:

$Q = \dot Q \cdot \Delta t$ (1)

Where:

$\dot Q$ - Volume rate, measured in feet per minute.

$\Delta t$ - Time, measured in minutes.

If we know that $\dot Q = 2000\,\frac{gal}{min}$ and $\Delta t = 120\,min$ , then the amount of water is:

$Q = \left(2000\,\frac{gal}{min} \right)\cdot (120\,min) \cdot \left(0.134\,\frac{ft^{3}}{gal} \right)$

$Q = 32160\,ft^{3}$

And the diameter of the cylindrical tank based on the capacity found above is determined by volume formula for a cylinder:

$Q = \frac{\pi}{4}\cdot D^{2}\cdot h$ (2)

Where:

$D$ - Diameter, measured in feet.

$h$ - Height, measured in feet.

If we know that $Q = 32160\,ft^{3}$ and $h = 12\,ft$ , then the minimum diameter is:

$D^{2} = \frac{4\cdot Q}{\pi\cdot h}$

$D = 2\cdot \sqrt{\frac{Q}{\pi\cdot h} }$

$D = 2\cdot \sqrt{\frac{32160\,ft^{3}}{\pi\cdot (12\,ft)} }$

$D \approx 58.415\,ft$

The minimum diameter of the cylindrical tank needed to store the quantity needed to put out the fire is approximately 58.415 feet.

8 0

2 years ago