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Andru [333]
3 years ago
11

Solve: 3 1/3 + (-2 1/4) + 1 5/6 =

Mathematics
1 answer:
Stella [2.4K]3 years ago
3 0

Answer:

91/12

Step-by-step explanation:

3 1/3 + (-2 1/4) + 1 5/6 = 91/12 or 7.58

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Maurinko [17]

5 minutes later the hand moves five minutes later

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Is this relation a function by using straight line test
Drupady [299]

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No

Step-by-step explanation:

Graph all points. They do not make a line.

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What can you say about the sum of consecutive odd numbers starting with 1? that is, evaluate 1, 1c3, 1c3c5, 1c3c5c7, and so on,
Mice21 [21]

Let us add consecutive odd numbers and try to find any relationship.

1. 1

2. 1+3 = 4 ( square of 2 i.e 2^{2} )

3. 1+3+5 = 9 ( 3^{2} )

4.  1+3+5+7 =  16 (4^{2} )

5. 1+3+5+7+9 = 25 (5^{2} )

6. 1+3+5+7+9+11 = 36 ( 6^{2} )

7. 1+3+5+7+9+11+13 = 49 (7^{2} )

If we notice, the sum of the consecutive odd integers in each case is equal to the square of the place where it lies. For example, the sum of numbers in seventh place is equal to 7^{2}. The sum of the numbers in the fifth line is equal to 5^{2}.

4 0
3 years ago
Help me please I’m begging you:(
alex41 [277]

Answer:

Chips = 14

Pretzel = 14

Cookie = 8

Popcorn = 13

Question Mark = 222

Step-by-step explanation:

First Equation:

Chips + Pretzel + Chips = 42

Third Equation: Chips = Pretzel.

This means that

Pretzel + Pretzel + Pretzel = 42

Pretzel = \frac{42}{3} =14

Chips = Pretzel

Chips = 14

Second Equation:

Cookie + Chips + Cookie = 30

We know that Chips = 14.

Cookie + 14 + Cookie = 30

Subtract 14 on both sides:

Cookie + Cookie = 16

Cookie = 16\div 2 =8.

Fourth Equation:

Cookie + Cookie + Popcorn = 29

We know that Cookie = 8.

8 + 8 + Popcorn = 29

16 + Popcorn = 29

Subtract 16 on both sides:

Popcorn = 13.

Question Mark:

(Popcorn + Popcorn) \times Cookie + Chips = (13 + 13) \times 8 + 14 = 26 \times 8 + 14 = 208+14=222

6 0
3 years ago
Read 2 more answers
B<br> D<br> A<br> C<br> side AC is extended to point D with m
Minchanka [31]

Answer:

im so confused

Step-by-step explanation:

5 0
3 years ago
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