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Vinil7 [7]
3 years ago
10

Tn+1=35-2Tn, T1=5 what is T20?

Mathematics
1 answer:
lbvjy [14]3 years ago
4 0

Answer:  3,495,265

<u>Step-by-step explanation:</u>

T_{n+1}=35-2T_n\quad and\quad T_1=5, then\\T_{1+1}=35-2(T_1)\implies T_2=35-2(5)\implies T_2=25\\T_{2+1}=35-2(T_2)\implies T_3=35-2(25)\implies T_3=-15\\T_{3+1}=35-2(T_3)\implies T_4=35-2(-15)\implies T_4=65\\T_{4+1}=35-2(T_4)\implies T_5=35-2(65)\quad \implies T_5=-95\\T_{5+1}=35-2(T_5)\implies T_6=35-2(-95)\implies T_6=225\\.\qquad \qquad \qquad \qquad \qquad \qquad \downarrow\\.\qquad \qquad \qquad \qquad \qquad \qquad \downarrow\\.\qquad \qquad \qquad \qquad \qquad \qquad \downarrow

T_{18+1}=35-2(T_{18})\implies T_{19}=35-2(873,825)\implies T_{19}=-1,747,615\\T_{19+1}=35-2(T_{19})\implies T_{20}=35-2(-1,747,615)\implies T_{20}=3,495,265

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Step-by-step explanation:


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a line is paralll yo y=4x-2 and intersects the point (5,-11). what is the equation of this parallel line
victus00 [196]

The equation of line parallel to given line is: y=4x-31

Step-by-step explanation:

Given equation of line is:

y = 4x-2

The equation of line is in slope-intercept form so the co-efficient of x is the slope of the line.

Let m1 be the slope of the given line

then

m1 = 4

Let m2 be the line that is parallel to given line

As we know that the slopes of parallel lines is equal so

m1=m2 = 4

The slope-intercept form of equation of line is:

y = m_2x+b

Putting the value of slope

y = 4x+b

to find the value of b, putting (5,-11) in the equation

-11 = 4(5) + b\\-11 = 20+b\\b = -11-20\\b = -31

Putting the value of b

y=4x-31

Hence,

The equation of line parallel to given line is: y=4x-31

Keywords: Equation of line, slope

Learn more about equation of line at:

  • brainly.com/question/3126500
  • brainly.com/question/3306327

#LearnwithBrainly

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3 years ago
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3 years ago
Use a graphing calculator to solve the equation -2sin(theta)= 1.2 in the interval from 0 to 2pi.
elena-s [515]

Answer:

\theta=\pi +arcsin(\frac{3}{5})\approx 3.785\\\\\theta=2\pi -arcsin(\frac{3}{5} ) \approx 5.64  

Step-by-step explanation:

As you can see from the graph I attached you, the possible solutions in the interval from 0 to 2π are approximately:

\theta=3.7\\\\and\\\\\theta=5.7

So, it's useful to solve the equation too, in order to verify the result:

-2sin(\theta)=1.2\\\\sin(\theta)=-\frac{3}{5}

Taking the inverse sine of both sides:

\theta=\pi +arcsin(\frac{3}{5})\approx 3.785\\\\\theta=2\pi -arcsin(\frac{3}{5} ) \approx 5.64

Using this result we can conclude the solutions in the interval from 0 to 2π are approximately:

\theta\approx 3.785\\\\\theta \approx 5.64

8 0
3 years ago
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