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Lina20 [59]
3 years ago
10

A piecewise function is shown below

Mathematics
1 answer:
Greeley [361]3 years ago
8 0

Answer:

p = 5/7

Step-by-step explanation:

The given function is:

g(x) = -3x^{2} - 2x + 8 for -4 ≦ x < 1

g(x) = -2x + 7p for 1 ≦ x ≦ 5

Part a)

A continuous function has no breaks, jumps or holes in it. So, in order for g(x) to be continuous, the point where g(x) stops during the first interval -4 ≦ x < 1 must be equal to the point where g(x) starts in the second interval 1 ≦ x ≦ 5

The point where, g(x) stops during the first interval is at x = 1, which will be:

-3(1)^{2}-2(1)+8=3

The point where g(x) starts during the second interval is:

-2(1)+7(p) = 7p - 2

For the function to be continuous, these two points must be equal. Setting them equal, we get:

3 = 7p - 2

3 + 2 = 7p

p = \frac{5}{7}

Thus the value of p for which g(x) will be continuous is \frac{5}{7}.

Part b)

We have to find p by setting the two pieces equal to each other. So, we get the equation as:

-3x^{2}-2x+8=-2x+7p\\\\ -3x^{2}+8=7p

Substituting the point identified in part (a) i.e. x=1, we get:

-3(1)^{2}+8=7p\\\\ 5=7p\\\\ p=\frac{5}{7}

This value agrees with the answer found in previous part.

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\bf cos(A)=\cfrac{\stackrel{adjacent}{3}}{\underset{hypotenuse}{5}}\qquad \qquad \stackrel{\textit{getting the opposite side}}{b=\pm\sqrt{5^2-3^2}}\implies b = \pm 4 \\\\\\ \stackrel{IV~Quadrant}{b = -4}\qquad \qquad sin(A)=\cfrac{\stackrel{opposite}{-4}}{\underset{hypotenuse}{5}} \\\\[-0.35em] ~\dotfill\\\\ cos(B)=\cfrac{\stackrel{adjacent}{12}}{\underset{hypotenuse}{13}}\qquad \qquad \stackrel{\textit{getting the opposite side}}{b=\pm\sqrt{13^2-12^2}}\implies b = \pm 5

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