What is-simplify 3ab x 2ac x 5b?

blagie [28]

0 - 18 = -18

-18 + 9 = -9 ft

7 0

2 years ago

The people of Bridgetown wanted to build a bridge across a nearby river. Since they were poor swimmers, their master Trigonomos

VikaD [51]

Answer:

60.2 m

Step-by-step explanation:

Let x represent the width of the river. The distance from the point across from the tree to the second point is 15 m. The angle from this point to the tree across the river is 76°.

This makes the side opposite the angle x, the width of the river. It also means the 15 m side is adjacent to this angle.

The ratio opposite/adjacent is the ratio for tangent; this gives us the equation

x/15 = tan(76)

Multiply both sides by 15:

15(x/15) = 15(tan(76))

x = 15(tan(76)) ≈ 60.2

5 0

3 years ago

What does the following equal? Please help me!

Juli2301 [7.4K]

Answer:

the first answer

Step-by-step explanation:

1/8 of the absolute value is 1/8 positive

anything from the absolute value is positive because absolute value is the value of how far away the number is from zero.

3 0

2 years ago

Read 2 more answers

A baseball has a diameter of 6 cm. If you wanted to replace the inside of the baseball with air, how much would be needed in cub

e-lub [12.9K]

This is just another way of asking "what is the volume of a sphere of 6cm"
The volume of a sphere is $V= \frac{3}{4} \pi R^{3}$
The R is 3cm in this problem since the diameter is twice the radius. For a 3cm radius sphere this is 113.1cm^3

3 0

2 years ago

Read 2 more answers

A car dealership sells 0, 1, or 2 luxury cars on any day. When selling a car, the dealer also tries to persuade the customer to

melisa1 [442]

Answer:

Mean = 1.42

Variance = 0.58

Step-by-step explanation:

Given: X denote the number of luxury cars sold in a given day, and Y denote the number of extended warranties sold.

Also, joint probability function of X and Y are given.

To find:

mean and variance of X

Solution:

From the given joint probability function of X and Y,

$P(X=0)=\frac{1}{6}\\P(X=1)=\frac{1}{12}+\frac{1}{6}=\frac{1+2}{12}=\frac{3}{12}\\P(X=2)=\frac{1}{12}+\frac{1}{3}+\frac{1}{6}=\frac{1+4+2}{12}=\frac{7}{12}$

Mean of X:

$E(X)=\sum XP(X)\\=0\left ( \frac{1}{6} \right )+1\left ( \frac{3}{12} \right )+2\left ( \frac{7}{12} \right )\\=0+\frac{3}{12}+\frac{14}{12}\\=\frac{17}{12}=1.42$

Variance of X:

$E(X^2)=\sum X^2P(X)\\=0^2\left ( \frac{1}{6} \right )+1^2\left ( \frac{3}{12} \right )+2^2\left ( \frac{7}{12} \right )\\=0+\frac{3}{12}+\frac{28}{12}\\=\frac{31}{12}$

$var(X)=E\left [ X^2 \right ]-\left ( E\left [ X \right ] \right )^2\\=\frac{31}{12}-\left ( \frac{17}{12} \right )^2\\=\frac{31}{12}-\frac{289}{144}\\=\frac{372-289}{144}\\=\frac{83}{144}\\=0.58$

5 0

3 years ago