i. 171
ii. 162
iii. 297
Solution,
n(U)= 630
n(I)= 333
n(T)= 168
i. Let n(I intersection T ) be X
<h3>ii.
n(only I)= n(I) - n(I intersection T)</h3><h3>
= 333 - 171</h3><h3>
= 162</h3>
<h3>
iii. n ( only T)= n( T) - n( I intersection T)</h3><h3>
= 468 - 171</h3><h3>
= 297</h3>
<h3>
Venn- diagram is shown in the attached picture.</h3>
Hope this helps...
Good luck on your assignment...
Short Answer 28
If I'm reading this correctly it is 28.
2 is a prime number.
7 is also a prime
They are multiplied together to give 2*7 = 14
When you divide 28/14 you get 2 which is the smallest prime.
28 <<< Answer
Hello from MrBillDoesMath!
Answer:
75
Discussion:
A plane triangle has 180 degrees. Using this in the diagram gives
x + 81 + angle BAC = 180 (***)
(The diagram is a bit fuzzy but I think the above numbers are accurate)
The diagram also shows that (156 + angle BAC )= 180 as a straight line has 180 degrees. So
angle BAC = 180 - 156 = 24
Substituting this in (***) above gives
x + 81 + 24 = 180 =>
x + 105 = 180 => (as 81 + 24 = 105)
x = 180 107 = 75
Check: Does
x + 81 + angle BAC = 180 ?
75 + 81 + 24 = 180. Yes
Thank you,
MrB
Answer:
The rule of the translation is (x,y) ----> (x+3,y-6)
The coordinates of the duck’s final position are (4,-3)
Step-by-step explanation:
we know that
A duck is going to fly from the coordinates (1, 3) then go 3 units right. And 6 units down
That means -----> The rule of the translation is
3 units right ----> x+3
6 units down ---> y-6
so
(x,y) ----> (x+3,y-6)
To find out the the coordinates of the duck’s final position, apply the rule of the translation to the duck’s original position
so
(1,3) ------> (1+3,3-6)
(1,3) ------> (4,-3)
Answer:
(2n + 1)[(2n + 1) � 1]
(2n + 1)(2n + 1 � 1)
(2n + 1)(2n), or 2n(2n + 1)
2n is an EVEN NUMBER, and adding 1 to an even number creates an ODD number
Therefore, 2n(2n+1)=EVEN NUMBER ODD NUMBER=EVEN NUMBER
Step-by-step explanation:
