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REY [17]
3 years ago
12

Help please? and steps

Mathematics
1 answer:
Montano1993 [528]3 years ago
8 0
P(x)=^3+4x-k
P(0) =5
P=20x^3
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I GIVE ANOTHER BRAINLIEST
dlinn [17]

Answer:

Answer Below

Step-by-step explanation:

Triangle #1

To solve this answer we need to multiply then <em>divide by 2</em>

3 x 8=24

24 ÷ 2=12

12

Triangle #2

Now we do the same thing!

3 x 8=24

24 ÷ 2=12

12

Rectangle #1

<em>Now we solve for the rectangle!</em>

6 x 8 = 48

48

Now we add all these together!

12 + 12 + 48 = 72

<em>The answer is D. 72 Square Units</em>

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2 years ago
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50 POINTS!!! In rectangle ABCD, AB = 6 cm, BC = 8 cm, and DE = DF. The area of triangle DEF is one-fourth the area of rectangle
aalyn [17]

Answer:

EF=4\sqrt{3}

Step-by-step explanation:

In rectangle ABCD, AB = 6, BC = 8, and DE = DF.

ΔDEF is one-fourth the area of rectangle ABCD.

We want to determine the length of EF.

First, we can find the area of the rectangle. Since the length AB and width BC measures 6 by 8, the area of the rectangle is:

A_{\text{rect}}=8(6)=48\text{ cm}^2

The area of the triangle is 1/4 of this. Therefore:

\displaystyle A_{\text{tri}}=\frac{1}{4}(48)=12\text{ cm}^2

The area of a triangle is half of its base times its height. The base and height of the triangle is DE and DF. Therefore:

\displaystyle 12=\frac{1}{2}(DE)(DF)

Since DE = DF:

24=DF^2

Thus:

DF=\sqrt{24}=\sqrt{4\cdot 6}=2\sqrt{6}=DE

Since ABCD is a rectangle, ∠D is a right angle. Then by the Pythagorean Theorem:

(DE)^2+(DF)^2=(EF)^2

Therefore:

(2\sqrt6)^2+(2\sqrt6)^2=EF^2

Square:

24+24=EF^2

Add:

EF^2=48

And finally, we can take the square root of both sides:

EF=\sqrt{48}=\sqrt{16\cdot 3}=4\sqrt{3}

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3 years ago
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wo mechanics worked on a car. The first mechanic charged $95 per hour, and the second mechanic charged $75per hour. The mechanic
Elenna [48]

5 hours and 25 minutes I think (Im not sure)

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2 years ago
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Angle x is such that sin x = a + b and cos x = a − b, where a and b are constants.
Mazyrski [523]

Answer:

Step-by-step explanation:

sin x=a+b

cos x=a-b

sin²x+cos²x=(a+b)²+(a-b)²=2a²+2b²

or 2a²+2b²=1

a²+b²=1/2 which is constant for all values of x

(ii)

\frac{\sin x}{\cos x}=\frac{a+b}{a-b}\\\tan x=\frac{a+b}{a-b}=2\\a+b=2a-2b\\b+2b=2a-a\\or a=3b

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Would you want only 1 gram of peanuts?
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1 Kilo
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