What radius of a circle is required to inscribe an equilateral triangle with an area of 270.633 cm2 and an altitude of 21.65 cm?

2 answers:

7 0

1.
All three angles are equal and their sum is 180. 
3 (3x-12) = 180 
9x -36 = 180 
9x = 180+36 
9x = 216 
x = 216/ 9 = 24 

2. 
Area of an equilateral triangle = (sqrt(3)/4 ) s^2 = 270.633 
s^2 = 270.633 / [ sqrt(3) /4] 
s^2 = (4)(270.633) / sqrt(3) 
s^2 = 625 
s = 25 (side) 

Follow the procedure in the link: we don't need the altitude. 
r = 25/sqrt(3) =14.43

solmaris [256]3 years ago

6 0

Answer:

r = 14.4

Step-by-step explanation:

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Which ordered pair is a solution of the equation? Y-4=7(x-6)

deff fn [24]

Answer:

(6,4)

Step-by-step explanation:

The equation is in 'point-slope' form.

$y-y_1=m(x-x_1)\\\rule{150}{0.5}\\(x_1,y_1) \rightarrow \text{a point that's given}\\\\m \rightarrow \text{slope}$

This means we can identify the point that was used in the equation.

$y-\boxed{y_1} =m(x-\boxed{x_1}) | y-\boxed{4}=7(x-\boxed{6})\\\rule{210}{0.5}\\y_1 = 4\\\\x_1 =6\\\rule{210}{0.5}\\(x_1,y_1) \rightarrow \boxed{(6,4)}$