What radius of a circle is required to inscribe an equilateral triangle with an area of 270.633 cm2 and an altitude of 21.65 cm?
2 answers:
1.
<span>All three angles are equal and their sum is 180. </span>
<span>3 (3x-12) = 180 </span>
<span>9x -36 = 180 </span>
<span>9x = 180+36 </span>
<span>9x = 216 </span>
<span>x = 216/ 9 = 24 </span>
<span>2. </span>
<span>Area of an equilateral triangle = (sqrt(3)/4 ) s^2 = 270.633 </span>
<span>s^2 = 270.633 / [ sqrt(3) /4] </span>
<span>s^2 = (4)(270.633) / sqrt(3) </span>
<span>s^2 = 625 </span>
<span>s = 25 (side) </span>
<span>Follow the procedure in the link: we don't need the altitude. </span>
<span>r = 25/sqrt(3) =14.43
</span>
Answer:
r = 14.4
Step-by-step explanation:
You might be interested in
slope basically directs how steep a line is. it’s formula is rise/run of y2-y1/x2-x1
Answer:
hope it helped u alot
Step-by-step explanation:
plsss give me braniest
Answer:
1/81
Step-by-step explanation:
9^2 = 81
We know that a^ -b = 1/a^b
9^-2
1/9^2
1/81
The common denominator is 3 because
example: 3x4= 12 and 3x3= 9
I believe the answer to your equation would be
-x^2/3 + 14x/9 + 5/27 - 140/27(-3x+1)
also this is my 69th answer in math and I find that fact mildly interesting
