What radius of a circle is required to inscribe an equilateral triangle with an area of 270.633 cm2 and an altitude of 21.65 cm?
2 answers:
1.
<span>All three angles are equal and their sum is 180. </span>
<span>3 (3x-12) = 180 </span>
<span>9x -36 = 180 </span>
<span>9x = 180+36 </span>
<span>9x = 216 </span>
<span>x = 216/ 9 = 24 </span>
<span>2. </span>
<span>Area of an equilateral triangle = (sqrt(3)/4 ) s^2 = 270.633 </span>
<span>s^2 = 270.633 / [ sqrt(3) /4] </span>
<span>s^2 = (4)(270.633) / sqrt(3) </span>
<span>s^2 = 625 </span>
<span>s = 25 (side) </span>
<span>Follow the procedure in the link: we don't need the altitude. </span>
<span>r = 25/sqrt(3) =14.43
</span>
Answer:
r = 14.4
Step-by-step explanation:
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