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3 years ago

15

The frequency table shows the results of tossing a ball 24 times into the four coloured sections on a carnival game Section | nu

mber of | Tosses Blue | 3 Green | 5 Red | 12 Yellow | 4 Based on the data on the table, how many times will the ball most likely land in the yellow section when it is tossed 200 times? A. 35 B. 40 C. 50 D. 65

1 answer:

Keith_Richards [23]3 years ago

8 0

Answer:

50

Step-by-step explanation:

you toss the ball 24 times, and of those 24 times, it lands 12 times on the yellow section, so 12/24= 0.5

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Please help. 20 points and brainliest.

julia-pushkina [17]

Answer:

minimum -45, maximum 32

Step-by-step explanation:

C=4x-3y

x≥0, y≥4, x+y≤15

Maximum value of C can be achieved at max x and min y

min y=4 => max x=15-4=11

C=4*11-3*4= 32

Minimum value of C can be achieved at min x and max y

min x=0, max y =15

C=4*0-3*15= -45

So answer is minimum -45, maximum 32

7 0

3 years ago

In the expression 4 to the power of 9 the number 9 i called the? A) base B)multiplier C) product D)exponent

harina [27]

In the expression 4 to the power of 9, the number 9 is called the D. exponent.
Number four here is the base, and the exponent is always shown as a superscript to the right of the base. It shows how many times you are supposed to multiply the base by itself.

3 0

4 years ago

Evaluate the line integral, where c is the given curve. (x + 9y) dx + x2 dy, c c consists of line segments from (0, 0) to (9, 1)

viktelen [127]

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=\int_C\langle x+9y,x^2\rangle\cdot\underbrace{\langle\mathrm dx,\mathrm dy\rangle}_{\mathrm d\mathbf r}$

The first line segment can be parameterized by $\mathbf r_1(t)=\langle0,0\rangle(1-t)+\langle9,1\rangle t=\langle9t,t\rangle$ with $0\le t\le1$ . Denote this first segment by $C_1$ . Then

$\displaystyle\int_{C_1}\langle x+9y,x^2\rangle\cdot\mathbf dr_1=\int_{t=0}^{t=1}\langle9t+9t,81t^2\rangle\cdot\langle9,1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(162t+81t^2)\,\mathrm dt$
$=108$

The second line segment ( $C_2$ ) can be described by $\mathbf r_2(t)=\langle9,1\rangle(1-t)+\langle10,0\rangle t=\langle9+t,1-t\rangle$ , again with $0\le t\le1$ . Then

$\displaystyle\int_{C_2}\langle x+9y,x^2\rangle\cdot\mathrm d\mathbf r_2=\int_{t=0}^{t=1}\langle9+t+9-9t,(9+t)^2\rangle\cdot\langle1,-1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(18-8t-(9+t)^2)\,\mathrm dt$
$=-\dfrac{229}3$

Finally,

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=108-\dfrac{229}3=\dfrac{95}3$

5 0

3 years ago

Tan x + sqrt(3) = - 2 tan x

Svet_ta [14]

9514 1404 393

Answer:

nπ -π/6 . . . for any integer n

Step-by-step explanation:

tan(x) +√3 = -2tan(x) . . . . . given

3tan(x) = -√3 . . . . . . . . . . . add 2tan(x)-√3

tan(x) = -√3/3 . . . . . . . . . . divide by 3

x = arctan(-√3/3) = -π/6 . . . . use the inverse tangent function to find x

This is the value in the range (-π/2, π/2). The tangent function repeats with period π, so the set of values of x that will satisfy this equation is ...

x = n·π -π/6 . . . . for any integer n

8 0

3 years ago

PLZZZZ HEEEEEEELLLPPP MEEEEE!

lesantik [10]

Answer:

144 it is D

Step-by-step explanation:

8 0

3 years ago

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