Question

The equation of the line WX is 2X plus Y equals -5 what is the equation of a line perpendicular to line WX in slope intercept form that contains point negative one -2

Answer 1

Answer:

$y = \frac{1}{2}x - \frac{3}{2}$

Step-by-step explanation:

The equation of the line WX is, 2x + y = - 5

⇒ y = - 2x - 5 .......... (1)

This equation is in slope-intercept form and the slope is - 2 and the y-intercept is - 5.

Now, if a line perpendicular to equation (1) having slope m then, m × (- 2) = - 1

⇒ $m = \frac{1}{2}$

{Since the product of slopes of two mutually perpendicular straight line is - 1}

Therefore, the equation of the perpendicular line is

$y = \frac{1}{2}x + c$, where c is a constant and we have to find it.

This above line passes through the point (-1,-2) and hence

$- 2 = \frac{1}{2}(- 1) + c$

⇒ $c = - \frac{3}{2}$

Therefore, the equation of the line will be $y = \frac{1}{2}x - \frac{3}{2}$ (Answer)