Question

Solve the system of linear equations by substitution.

Answer 1

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2x + 3y = 0:

1. Subtract 3y from both sides

2x = -3y

2. Divide both sides by 2

x = -3y over 2

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1. Subtract 2x from both sides

3y = -2x

2. Divide both sides by 3

y = -2x over 3

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8x + 9y = 18:

1. Subtract 9y from both sides

8x = 18 - 9y

2. Divide both sides by 8

x = 18 - 9y over 8

3. Factor out the common term 9

x = 9(2 - y) over 8

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1. Subtract 8x from both sides

9y = 18 - 8x

2. Divide both sides by 9

y = 18 - 8x over 9

3. Factor out the common term 2

y = 2(9-4x) over 9