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ELEN [110]
3 years ago
14

What is 8 2/7 -1 1/7

Mathematics
1 answer:
Komok [63]3 years ago
6 0

Answer:

7.14285714286

Step-by-step explanation:

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use the elimination method to solve the system of equations. choose the correct ordered pair x-y=2 2x+3y=14
Salsk061 [2.6K]
Solve using the p method
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3 years ago
A 2-column table with 4 rows. Column 1 is labeled Store with entries A, B, C, D. Column 2 is labeled Advertised Bread Prices wit
attashe74 [19]

answer is C

Step-by-step explanation:

i got it right and it looked like no one would help you so

6 0
4 years ago
The difference between two numbers is 10. The smaller number is 8.
Lunna [17]

Answer:

x - 8 = 10

Step-by-step explanation:

The smallest number is 8 so it's subtracting 8. 10 is the difference between the two numbers because it's the answer.

4 0
3 years ago
What is the recursive rule for the sequence? -1,-0.5,0,0.5,1,...
Umnica [9.8K]

9514 1404 393

Answer:

  C

Step-by-step explanation:

The subscript (n-1) is used to indicate the term previous to term (n). In this sequence, each term is 0.5 more than the previous term, so the recursive relation ...

  a_n=a_{n-1}+0.5

is the appropriate one. This matches choice C.

__

<em>Additional comment</em>

Of course, if the next term is 0.5 more than the last, then the previous term is 0.5 less than the present one. The sequence can be described in this "backward" fashion by the recursive relation of choice A. While that <em>does work</em> to describe the sequence, it is usually <em>not</em> the form we desire for a recursive relation.

3 0
3 years ago
On a particular production line,the likelihood that a light bulb is defective is 5%. Ten light bulbs are randomly selected. What
KengaRu [80]

Answer:

Mean and Variance of the number of defective bulbs are 0.5 and 0.475 respectively.

Step-by-step explanation:

Consider the provided information,

Let X is the number of defective bulbs.

Ten light bulbs are randomly selected.

The likelihood that a light bulb is defective is 5%.

Therefore sample size is = n = 10

Probability of a defective bulb = p = 0.05.

Therefore, q = 1 - p = 1 - 0.05 = 0.95

Mean of binomial random variable: \mu=np

Therefore, \mu=10(0.05)=0.5

Variance of binomial random variable: \sigma^2=npq

Therefore, \sigma^2=10(0.05)(0.95)=0.475

Mean and Variance of the number of defective bulbs are 0.5 and 0.475 respectively.

5 0
3 years ago
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