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3 years ago

Choose Yes or No to tell if the digit in the ones place is 110 the value of the digit in the tens place.

Mathematics

1 answer:

Alja [10]3 years ago

4 0

Answer:

Step-by-step explanation:

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kalen has a 60 gallon fuel tank. the fuel gauge points to 1/4 how mcuh fuel does she need to buy to fill the tank

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Answer:

45 Gallons

Step-by-step explanation:

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3 years ago

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Describe the graph of x>-2

tekilochka [14]

Answer:

A dotted line going through -2 on the x axis, with the right side of the graph shaded in.

hope this helps!

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3 years ago

What is the slope of a line that passes through the points (-3,-6) and (8, 16) ?

denis-greek [22]

Answer:

slope = 2

Step-by-step explanation:

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2 years ago

Need to pass this test to graduate

Paraphin [41]

The 1st graph has vertex in (-3, -3) which can be translated into
Horizontal shift left 3
Vertical shift down 3
Other than that, the graph shows y=x^2 so it wasn't compressed or stretched

The 2nd graph has vertex in (0, 0) which mean there is no vertical and horizontal shift. But the graph is facing down and it was slimmer than y=x^2 graph. When x=1, the result is y=3 which was 3 times more than it supposed to be.
The graph must be:
Reflection across x-axis
Vertical stretch of 3

The 3rd graph has vertex in (3, -3) which can be translated into
Horizontal shift right 3
Vertical shift down 3
Same as the 1st graph, the 3rd graph shows y=x^2 so it wasn't compressed or stretched.

5 0

3 years ago

Water is drained out of tank, shaped as an inverted right circular cone that has a radius of 4cm and a height of 16cm, at the ra

bearhunter [10]

Answer:

$\frac{dh}{dt}=-\frac{1}{2\pi}cm/min$

Step-by-step explanation:

From similar triangles, see diagram in attachment

$\frac{r}{4}=\frac{h}{16}$

We solve for $r$ to obtain,

$r=\frac{h}{4}$

The formula for calculating the volume of a cone is

$V=\frac{1}{3}\pi r^2h$

We substitute the value of $r=\frac{h}{4}$ to obtain,

$V=\frac{1}{3}\pi (\frac{h}{4})^2h$

This implies that,

$V=\frac{1}{48}\pi h^3$

We now differentiate both sides with respect to $t$ to get,

$\frac{dV}{dt}=\frac{\pi}{16}h^2 \frac{dh}{dt}$

We were given that water is drained out of the tank at a rate of $2cm^3/min$

This implies that $\frac{dV}{dt}=-2cm^3/min$ .

Since we want to determine the rate at which the depth of the water is changing at the instance when the water in the tank is 8cm deep, it means $h=8cm$ .

We substitute this values to obtain,

$-2=\frac{\pi}{16}(8)^2 \frac{dh}{dt}$

$\Rightarrow -2=4\pi \frac{dh}{dt}$

$\Rightarrow -1=2\pi \frac{dh}{dt}$

$\frac{dh}{dt}=-\frac{1}{2\pi}$

3 0

3 years ago

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