What is the simplified value of the expression below? One-third divided by two-thirds 0 One-third One-half 1

Which inequality represents all value of x for which the quotient is defined √7x^2 ÷ √3x

pentagon [3]

Answer:

$\sqrt{21} x^{3} /3$

Step-by-step explanation:

hope this helps

5 0

3 years ago

Read 2 more answers

Use a calculator to find decimal estimates to two decimal places (hundredths) for the following irrational number: √19

lara [203]

Answer:

The answer is 4.35, rounded two decimals to hundredths place.

some text here to make the answer slightly longer for some good reasons. yep.

6 0

2 years ago

Describe how you would estimate the square root of 100

max2010maxim [7]

I am not completely sure but Khan Academy might show how to do that. Or it might at least give an example.

5 0

3 years ago

Solve the system with elimination. x - y = 10 3x - 2y = 25

raketka [301]

Answer:

Step-by-step explanation:

{x,y}={5,-5}

8 0

2 years ago

Several years ago, 50% of parents who had children in grades K-12 were satisfied with the quality of education the students r

galina1969 [7]

Answer:

The 95% confidence interval for the proportion of parents that are satisfied with their children's education is (0.4118, 0.4618). 0.5 is not part of the confidence interval, so this represents evidence that parents' attitudes toward the quality of education have changed.

Step-by-step explanation:

We have to see if 50% = 0.5 is part of the confidence interval.

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 1095, \pi = \frac{478}{1095} = 0.4365$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4365 - 1.96\sqrt{\frac{0.4365*0.5635}{1095}} = 0.4118$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4365 + 1.96\sqrt{\frac{0.4365*0.5635}{1095}} = 0.4612$

The 95% confidence interval for the proportion of parents that are satisfied with their children's education is (0.4118, 0.4618). 0.5 is not part of the confidence interval, so this represents evidence that parents' attitudes toward the quality of education have changed.

5 0

3 years ago