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Goryan [66]
3 years ago
12

The distance between two cities is 1900 km. How long will it take, in h, to drive from one city to the other if your average spe

ed is 84 mi/h?
Mathematics
1 answer:
OLEGan [10]3 years ago
3 0

Answer: 14 hours

Step-by-step explanation:

from the formular;

speed = distance / time

time = distance / speed

distance = 1900km

speed = 84 mi/h

we have to change this to km/h since our distance is in km

1 mile = 1. 609km

84mile = x

cross multiply

x = 84 × 1. 609

x = 135. 156km

speed = 135. 156km/h

Time = distance / speed

time= 1900 / 135. 166

time = 14. 058

time = 14 hours approximately

Therefore it takes 14 hours to drive from one city to the other.

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Write an equation of the line in slope-intercept form for the graph<br><br> Please helppp
Anvisha [2.4K]

Answer:

y=-4/3+2

Step-by-step explanation:

Sin the slope is going up to the left we can already infer that it is going to be a negative. Still we do the equation y2-y1/x2-x1. In this case 0 is x1 and 2 is y1, 3 is x2, and -2 is y2. Once inserted into the equation you get -2-2/3-0 which equals -4/3 and the y intercept is 2 since thats the point shown were it intercepts the y-axis

8 0
3 years ago
Vera's office recycled a total of 4 kilograms of paper over 2 weeks. After 7 weeks, how many kilograms of paper will Vera's offi
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3 years ago
Write the equation in slope-intercept form through the point (-4, -7) and is perpendicular to the line y = -(7/4)x + 4 and graph
Scilla [17]

You have to write the equation for a line that crosses the point (-4, -7) and is perpendicular to the line

y=-\frac{7}{4}x+4

When you have to determine a line that is perpendicular to a known line, you have to keep in mind that the slope of the perpendicular line will be the negative inverse of the first one.

If for exampla you have two lines, the first one being:

y_1=mx+b

And the second one, that is perpedicular to the one above:

y_2=nx+c

The slope of the second one is the negative inverse of the first one:

n=-\frac{1}{m}

The slope of the given line y=-7/4+4 is m=-7/4

So the slope of the perpendicular line has to ve the inverse negative of -7/4

\begin{gathered} n=-(-\frac{4}{7}) \\ n=\frac{4}{7} \end{gathered}

Considering it has to pass through the point (-4,-7) and that we already determined its slope, you can unse the point slope formula to determine the equation of the perpendicular line:

y-y_1=m(x-x_1)

replace with the coordinates of the point and the slope and calculate:

\begin{gathered} y-(-7)=\frac{4}{7}(x-(-4)) \\ y+7=\frac{4}{7}(x+4) \\ y+7=\frac{4}{7}x+\frac{16}{7} \end{gathered}

Subtract 7 to both sides of the equation to write it in slope-intercept form:

\begin{gathered} y+7-7=\frac{4}{7}x+\frac{16}{7}-7 \\ y=\frac{4}{7}x-\frac{33}{7} \end{gathered}

Now you can graph both lines

8 0
1 year ago
Which one is a better deal?
saul85 [17]
12 pack is a better deal
5 0
3 years ago
I need to figure out the answer
ANEK [815]
Hello there,

If c=-2 just plug in -2 for every c you see.

(-2)²-7(-2)-8
This simplifies to
4+14-8
18-8
10

Hope this helps!
3 0
3 years ago
Read 2 more answers
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