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3 years ago

1.5d + 3.25 = 1 + 2.25d ---What are the steps to find x?

1 answer:

3 0

Do u mean d?

1.5d +3.25 = 1 +2.25d
3.25 = 1 + .75d -1.5d on both sides
2.25 = .75d subtraction 1 on both sides
3 = d divide both sides by .75

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Can u change 28/140 into a percent

Anton [14]

Answer:

Step-by-step explanation:

28/140=0.2

5 0

3 years ago

In how many ways can a committee of five women and four men be formed from a group of seven women and seven men?

vekshin1

Number of combinations of 5 women from 7 = 7C5 = 7*6 / 2 = 21
for men its 7C4 = 7*6*5 / 3*2 = 35

Total number of ways = 21*35 = 735

6 0

3 years ago

Advertising expenses are a significant component of the cost of goods sold. Listed below is a frequency distribution showing the

Alexxandr [17]

Answer:

Step-by-step explanation:

The table can be computed as:

Advertising Expenses ($ million) Number of companies

25 up to 35 4

35 up to 45 19

45 up to 55 27

55 up to 65 16

65 up to 75 9

TOTAL 75

Let's find the probabilities first:

$P(25 - 35) = P \Big(\dfrac{25-50.93}{10.80}$

For 35 up to 45

$P(35 - 45) = P \Big(\dfrac{35-50.93}{10.80}$

For 45 up to 55

$P(45 - 55) = P \Big(\dfrac{45-50.93}{10.80}$

For 55 up to 65

$P(55 - 65) = P \Big(\dfrac{55-50.93}{10.80}$

For 65 up to 75

$P(65 - 75) = P \Big(\dfrac{65-50.93}{10.80}$

Chi-Square Table can be computed as follows:

Expense No of Probabilities(P) Expe $(O-E)^2$ $\dfrac{(O-E)^2}{E}$

compa cted E (n*p)

nies (O)

25-35 4 0.0612 75*0.0612 = 4.59 0.3481 0.0758

35-45 19 0.2218 75*0.2218 = 16.635 5.5932 0.3362

45-55 27 0.3568 75*0.3568 = 26.76 0.0576 0.021

55-65 16 0.2552 75*0.2552 = 19.14 9.8596 0.5151

65-75 9 0.0839 75*0.0839 = 6.2925 7.331 1.1650

$\sum \dfrac{(O-E)^2}{E}= 2.0492$

Using the Chi-square formula:

$X^2 = \dfrac{(O-E)^2}{E} \\ \\ Chi-square \ X^2 = 2.0942$

Null hypothesis:

$H_o: \text{The population of advertising expenses follows a normal distribution}$

Alternative hypothesis:

$H_a: \text{The population of advertising expenses does not follows a normal distribution}$

Assume that:

$\alpha = 0.02$

degree of freedom:

= n-1

= 5 -1

= 4

Critical value from $X^2 = 11.667$

Decision rule: To reject $H_o \ if \ X^2$ test statistics is greater than $X^2$ tabulated.

Conclusion: Since $X^2 = 2.0942$ is less than critical value 11.667. Then we fail to reject $H_o$

6 0

3 years ago

Help with number three!

natka813 [3]

1 hour and 35 minutes without the break. 60 minutes in an hour, subtract 15 from 50 = 35 minutes. It starts at 3 and ends at 4, which is 1 hour apart. Because there us a break you subtract 30 from the minutes , 35-30=5. So you have 1 hour and 5 minutes.

7 0

3 years ago

WHATS IS -5x 2/7= I NEED HELP PLEASE

Kipish [7]

-5x 2/7 =

−10x/7

srry if it is wrong man but that is what i got

4 0

3 years ago