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2 years ago

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For basketball tryouts, Kiana ran two laps in a total of 28.5 seconds. In the second lap, she beat her first lap by 3 seconds. W

rite an equation to represent the situation. I a clase Solve the equation to calculate how long to run the second lap?

1 answer:

yanalaym [24]2 years ago

8 0

Answer:add 6

Step-by-step explanation:

yo have to add 5 then subtract to get answer

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KonstantinChe [14]

The bed room would be 2/8

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3 years ago

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Dimas is playing a game that uses a number cube. The sides of the cube are labeled from 1 to 6. Dimas wants to roll a 2 or a 3.

Tcecarenko [31]

Answer:

The probability that he will roll a 2 or a 3

$P((E_{1} UE_{2} ) = \frac{1}{3}$

Step-by-step explanation:

<u><em>Step(i);-</em></u>

Dimas is playing a game that uses a number cube.

The sides of the cube are labelled from 1 to 6

The total number of Exhaustive cases

n(S) = {1,2,3,4,5,6} = 6

<u><em>Step(ii):-</em></u>

Let E₁ be the event of roll a '2'

n(E₁) = 1

The probability that Dimas wants to roll a '2'

$P(E_{1} ) = \frac{n(E_{1} )}{n(S)} = \frac{1}{6}$

Let E₂ be the event of roll a '3'

n(E₂) = 1

The probability that Dimas wants to roll a '3'

$P(E_{2} ) = \frac{n(E_{2} )}{n(S)} = \frac{1}{6}$

But E₁ and E₂ are mutually exclusive events

P(E₁∩E₂) = 0

<u><em>Step(iii):-</em></u>

The probability that he will roll a 2 or a 3

we have P((E₁UE₂) = P(E₁)+P(E₂)

= $= \frac{1}{6} + \frac{1}{6} = \frac{2}{6} = \frac{1}{3}$

$P((E_{1} UE_{2} ) = \frac{1}{3}$

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3 years ago

Juan and Ari went to the farmers market to buy fruit. Juan’s bag of apples that he bought weighed StartFraction 31 over 7 EndFra

Troyanec [42]

Answer:

2

Step-by-step explanation:

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3 years ago

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Terra writes the following proof for the theorem: If the diagonals of a quadrilateral bisect each other, the quadrilateral is a

Brrunno [24]

Answer:

you are correct and pls dont delete this anwser if i get it wrong side B

Step-by-step explanation:

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3 years ago

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10(1+3x)=-20 and -5x-8(1+7x)=-8 <br> With steps

SOVA2 [1]

(1)

10(1+3x)=-20

Cross multiply.

10+30x=-20

Isolate x on one side. So you would subtract 10 on each side. and one side will cross each other out. leaving you with,

30x=-20-10

Subtract 10 from -20.

30x=-30

Divide each side by 30 to get x.

30x÷30=-30÷30

Therefore,

x=-1

(2)

-5x-8(1+7x)=-8

Cross multiply -8(1+7x)

-5x-8-56x=-8

Isolate all x's on one side. So you would add 8 on each side. and one side will cross each other out. leaving you with,

-5x-56x=-8+8

Add 8 to -8.

-5x-56x=0

Subtract -56x from -5x

-61x=0

Divide each side by -61

-61x÷-61=0÷-61

Therefore,

x=0

6 0

3 years ago