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Anon25 [30]
2 years ago
11

For basketball tryouts, Kiana ran two laps in a total of 28.5 seconds. In the second lap, she beat her first lap by 3 seconds. W

rite an equation to represent the situation. I a clase Solve the equation to calculate how long to run the second lap?​
Mathematics
1 answer:
yanalaym [24]2 years ago
8 0

Answer:add 6

Step-by-step explanation:

yo have to add 5 then subtract to get answer

You might be interested in
Solve 2x3 + x2 - 15x completely by factoring.
zhuklara [117]
Answer:  [D]:  " x = 0, -3, 5/2 "  .

{Assuming:  " 2x³ + x²  − 15x = 0 ".}.
__________________________________________
Explanation:
___________________________________
Given:
_________________________________
     2x³ + x² − <span>15x ;
 __________________________________
</span>        →  (2x³ + x²) − 15x ;
  
        →   2x³ + x² − 15x  =   x * (2x² + x − 15) ;
         
        →  Factor the expression:  "(2x² + x − 15)" ;
                                     
             → (2x² + x − 15) =  
            
            →   2x² − 5x + 6x − 15 ;

           →  Add the "first TWO (2) terms", and pull out the "like factors" ;                                       →  x*(2x − 5) ;

           →  Add the "last TWO (2) terms, pulling out "common factors";
                            →  3*(2x − 5) ;

           →  Now, add up the previous FOUR (4) terms; to get:

                            → (x + 3)(2x − 5) ;  

           → Now, we have factored the:

                    "(2x² + x − 15)" of:  " x*(2x² + x − 15) " ; 

           →  So we add the "x"; and write the entire factored expression:
______________________________________________________
                      →  x*(x + 3)(2x − 5) ;           
_____________________________________
Now, assume the question is asking to solve for "x" by factoring;
   when the expression is "equal to zero" ;
_______________________________________
That is, when:  

                →  x*(x + 3)(2x − 5) = 0 ;
____________________________________________
Since we have THREE (3) multiplicands;  and anything times "0" equals "0" ;
    this equation holds true when:
________________________________
  1) x = 0 ;
_______________
  2) (x + 3) = 0 ;
  
Subtract "3" from each side of the equation;

   x + 3 − 3 = 0 − 3 ; 
  
         x = -3 ; 
_______________________
3)  2x − 5 = 0 ; 

Add "5" to each side of the equation;

2x − 5 + 5 = 0 + 5 ;

2x = 5 ; Now, divide EACH side of the equation by "2" ; to isolate "x" on one side of the equation; and to solve for "x" ; 

2x/2 = 5/2 ;

x = 5/2; or, write as 2.5; or write as 2<span>½ .
</span>_____________________________________
Put simply, the equation is true when:
_________________________________________
    x = 0, -3, 5/2 ;  which is: Answer choice: [D].
_________________________________________

7 0
2 years ago
Please help!!! It'd be awesome if you could show a step-by-step thank you!!! I am voting brainly
Kazeer [188]

Answer:

77.75%

Step-by-step explanation:

We just have to find the sums of the product of Joey's averages and their contribution to the total grade.

Test: 0.45 * 0.8 = 0.36 = 36%

Quizzes: 0.3 * 0.85 = 0.255 = 25.5%

Homework: 0.25 * 0.65 = 0.1625 = 16.25%

Total: 36% + 25.5% + 16.25% = 77.75%

4 0
2 years ago
Test the claim that the mean GPA of night students is larger than 3.1 at the .10 significance level. The null and alternative hy
Alborosie

Answer:

H 0 : μ = 3.1    H 1 : μ > 3.1

And this test is defined a a right tailed test since the symbol for the alternative hypothesis H1 is >.

t = \frac{3.13-3.1}{\frac{0.03}{\sqrt{75}}}= 8.66

df = n-1=75-1 =74

The p value is:

p_v = P(t_{74} >8.66) =3.65x10^{-13}

The significance level is: 0.1 or 10%

And since the p value is very low compared to the significance level we have enough evidence to:

Reject the null hypothesis

Step-by-step explanation:

For this case we want to test the claim that mean GPA of night students is larger than 3.1 at the .10 significance level. The claim needs to be on the alternative hypothesis so then we have the following system of hypothesis:

H 0 : μ = 3.1    H 1 : μ > 3.1

And this test is defined a a right tailed test since the symbol for the alternative hypothesis H1 is >.

We have the following info given:

\bar X = 3.13 , s =0.03 , n =75

The statistic to check the hypothesis is given by:

t = \frac{\bar X -\mu}{\frac{s}{\sqrt{n}}}

Replacing the info given we got:

t = \frac{3.13-3.1}{\frac{0.03}{\sqrt{75}}}= 8.66

The degrees of freedom are given by:

df = n-1=75-1 =74

The p value since is a right tailed ted is given by:

p_v = P(t_{74} >8.66) =3.65x10^{-13}

The significance level is 0.1 or 10%

And since the p value is very low compared to the significance level we have enough evidence to:

Reject the null hypothesis

6 0
2 years ago
Which is the correct classification of sqrt 32
labwork [276]

Answer:

irrational number, nonrepeating decimal

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Sean and Leah are playing a computer game. Sean scored 72,491points. Leah scored 19,326 points more than Sean.How many points di
natita [175]
72,491 + 19,326 = 91,817
Leah scored 91,817 points
4 0
2 years ago
Read 2 more answers
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