Answer:
(3,7) and (-3,-5)
Step-by-step explanation:
To solve the system of equations, graph both functions. The (x,y) point(s) where the functions intersect is the solution(s).
See attached picture.


so just find the "adjacent" side, using the pythagorean theorem, and even though the square root can give you +/-, use the positive one, assuming the angle is in the 1st quadrant
keeping in mind, that the 2nd quadrant is feasible as well, since the opposite side of +2 can also be in the 2nd quadrant
but anyhow, use the I quadrant
10x10= 100
10x10x10=1000
100+1000=10,000
Answer:
70130000000
Step-by-step explanation:
(Assuming that that 7013 is supposed to be 7013 not 7.013), We will move the decimal place to the right 7 times, since it is 10 to the power of 7. Since the decimal place is at the end of the number, we have to add 7 zeros. This becomes 70130000000.
Answer: Our required probability is 0.278.
Step-by-step explanation:
Since we have given that
Probability that a player has a batting average = 0.260
Probability of success = 0.260
Probability of failure = 1-0.260 = 0.74
Number of times at bat = 4
Probability that the player will get two or more hits in his next four times at bat is given by

Hence, our required probability is 0.278.