7D%7Bc%7Cc%7D%20%5Cbf%20f%28x%29%20%26%20%5Cbf%20%5Cdisplaystyle%20%5Cint%20%5Crm%20%5C%3Af%28x%29%20%5C%3A%20dx%5C%5C%20%5C%5C%20%5Cfrac%7B%5Cqquad%20%5Cqquad%7D%7B%7D%20%26%20%5Cfrac%7B%5Cqquad%20%5Cqquad%7D%7B%7D%20%5C%5C%20%5Csf%20k%20%26%20%5Csf%20kx%20%2B%20c%20%5C%5C%20%5C%5C%20%5Csf%20sinx%20%26%20%5Csf%20-%20%5C%3A%20cosx%2B%20c%20%5C%5C%20%5C%5C%20%5Csf%20cosx%20%26%20%5Csf%20%5C%3A%20sinx%20%2B%20c%5C%5C%20%5C%5C%20%5Csf%20%7Bsec%7D%5E%7B2%7D%20x%20%26%20%5Csf%20tanx%20%2B%20c%5C%5C%20%5C%5C%20%5Csf%20%7Bcosec%7D%5E%7B2%7Dx%20%26%20%5Csf%20-%20cotx%2B%20c%20%5C%5C%20%5C%5C%20%5Csf%20secx%20%5C%3A%20tanx%20%26%20%5Csf%20secx%20%2B%20c%5C%5C%20%5C%5C%20%5Csf%20cosecx%20%5C%3A%20cotx%26%20%5Csf%20-%20%5C%3A%20cosecx%20%2B%20c%5C%5C%20%5C%5C%20%5Csf%20tanx%20%26%20%5Csf%20logsecx%20%2B%20c%5C%5C%20%5C%5C%20%5Csf%20%5Cdfrac%7B1%7D%7Bx%7D%20%26%20%5Csf%20logx%2B%20c%5C%5C%20%5C%5C%20%5Csf%20%7Be%7D%5E%7Bx%7D%20%26%20%5Csf%20%7Be%7D%5E%7Bx%7D%20%2B%20c%5Cend%7Barray%7D%7D%20%5C%5C%20%5Cend%7Bgathered%7D%5Cend%7Bgathered%7D%5Cend%7Bgathered%7D" id="TexFormula1" title="\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin{array}{c|c} \bf f(x) & \bf \displaystyle \int \rm \:f(x) \: dx\\ \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf k & \sf kx + c \\ \\ \sf sinx & \sf - \: cosx+ c \\ \\ \sf cosx & \sf \: sinx + c\\ \\ \sf {sec}^{2} x & \sf tanx + c\\ \\ \sf {cosec}^{2}x & \sf - cotx+ c \\ \\ \sf secx \: tanx & \sf secx + c\\ \\ \sf cosecx \: cotx& \sf - \: cosecx + c\\ \\ \sf tanx & \sf logsecx + c\\ \\ \sf \dfrac{1}{x} & \sf logx+ c\\ \\ \sf {e}^{x} & \sf {e}^{x} + c\end{array}} \\ \end{gathered}\end{gathered}\end{gathered}" alt="\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin{array}{c|c} \bf f(x) & \bf \displaystyle \int \rm \:f(x) \: dx\\ \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf k & \sf kx + c \\ \\ \sf sinx & \sf - \: cosx+ c \\ \\ \sf cosx & \sf \: sinx + c\\ \\ \sf {sec}^{2} x & \sf tanx + c\\ \\ \sf {cosec}^{2}x & \sf - cotx+ c \\ \\ \sf secx \: tanx & \sf secx + c\\ \\ \sf cosecx \: cotx& \sf - \: cosecx + c\\ \\ \sf tanx & \sf logsecx + c\\ \\ \sf \dfrac{1}{x} & \sf logx+ c\\ \\ \sf {e}^{x} & \sf {e}^{x} + c\end{array}} \\ \end{gathered}\end{gathered}\end{gathered}" align="absmiddle" class="latex-formula">
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![\int \frac{dx}{x} = log(x) + c \\ \int \frac{f \prime(x)}{f(x)} = log \mid \: f(x) \mid + c \\ \int \: tan(x)dx = \int \: \frac{sin(x)}{cos(x)} dx \\ = - log|cos(x)| + c \\ = log |sec(x)| + c \\ the \: same \: rule \: goes \: for \: cot...etc.\\\int {sec}^{2}(x)dx=|tan(x)|+c\\let u=tanx\\ \frac{du}{dx}={sec}^{2}(x)\rightarrow {du}={sec}^{2}(x)dx\\ \int du=|u|+c\\ \therefore tan|x|+c](https://tex.z-dn.net/?f=%20%5Cint%20%5Cfrac%7Bdx%7D%7Bx%7D%20%20%3D%20log%28x%29%20%2B%20c%20%5C%5C%20%20%5Cint%20%5Cfrac%7Bf%20%5Cprime%28x%29%7D%7Bf%28x%29%7D%20%20%3D%20log%20%20%5Cmid%20%5C%3A%20f%28x%29%20%5Cmid%20%2B%20c%20%5C%5C%20%20%5Cint%20%5C%3A%20tan%28x%29dx%20%3D%20%20%5Cint%20%5C%3A%20%20%5Cfrac%7Bsin%28x%29%7D%7Bcos%28x%29%7D%20dx%20%5C%5C%20%20%3D%20%20-%20log%7Ccos%28x%29%7C%20%20%2B%20c%20%20%5C%5C%20%20%3D%20log%20%7Csec%28x%29%7C%20%20%2B%20c%20%5C%5C%20the%20%5C%3A%20same%20%5C%3A%20rule%20%5C%3A%20goes%20%5C%3A%20for%20%5C%3A%20cot...etc.%5C%5C%5Cint%20%7Bsec%7D%5E%7B2%7D%28x%29dx%3D%7Ctan%28x%29%7C%2Bc%5C%5Clet%20u%3Dtanx%5C%5C%20%5Cfrac%7Bdu%7D%7Bdx%7D%3D%7Bsec%7D%5E%7B2%7D%28x%29%5Crightarrow%20%7Bdu%7D%3D%7Bsec%7D%5E%7B2%7D%28x%29dx%5C%5C%20%5Cint%20du%3D%7Cu%7C%2Bc%5C%5C%20%5Ctherefore%20tan%7Cx%7C%2Bc)
Step-by-step explanation:
Am not sure what your question is? But if you are asking about a proof, then you may use Taylor series to prove these integrals...
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Answer:
Step-by-step explanation:
Domain:- (-∞,∞)
Range:- [2,∞)
Since the scale is 1:83, the real airplane is 83 times longer than the model airplane.
real length = 10.5 in * 83 = 871.5 in
Now we convert 871.5 in into ft.
1 ft = 12 in, so 1 in = 1/12 ft
We divide the number of inches by 12 to find the number of feet.
871.5 in = 871.5/12 ft = 72.625 ft
Answer:
Hello,
answer C
Step-by-step explanation:
![f(x)=x^2+2x-8\\\\=x^2-4x+2x-8\\\\=x(x-4)+2(x-4)\\\\=(x-4)(x+2)\\\\Answer\ C](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E2%2B2x-8%5C%5C%5C%5C%3Dx%5E2-4x%2B2x-8%5C%5C%5C%5C%3Dx%28x-4%29%2B2%28x-4%29%5C%5C%5C%5C%3D%28x-4%29%28x%2B2%29%5C%5C%5C%5CAnswer%5C%20C)
Answer:
Z = -6.3
Step-by-step explanation:
Given that:
![\mathbf{H_o :p= 0.28}](https://tex.z-dn.net/?f=%5Cmathbf%7BH_o%20%3Ap%3D%200.28%7D)
![\mathbf{H_o :p < 0.28}](https://tex.z-dn.net/?f=%5Cmathbf%7BH_o%20%3Ap%20%3C%200.28%7D)
Since the alternative hypothesis is less than 0.28, then this is a left-tailed hypothesis.
Sample sixe n = 800
= 0.217
The standard error ![S.E(p) = \sqrt{\dfrac{p(1-p)}{n}}](https://tex.z-dn.net/?f=S.E%28p%29%20%3D%20%5Csqrt%7B%5Cdfrac%7Bp%281-p%29%7D%7Bn%7D%7D)
![S.E(p) = \sqrt{\dfrac{0.28(1-0.28)}{800}}](https://tex.z-dn.net/?f=S.E%28p%29%20%3D%20%5Csqrt%7B%5Cdfrac%7B0.28%281-0.28%29%7D%7B800%7D%7D)
![S.E(p) \simeq0.015](https://tex.z-dn.net/?f=S.E%28p%29%20%5Csimeq0.015)
Since this is a single proportional test, the test statistics can be computed as:
![Z = \dfrac{\hat p - p}{\sqrt{\dfrac{p(1-p)}{n}}}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cdfrac%7B%5Chat%20p%20-%20p%7D%7B%5Csqrt%7B%5Cdfrac%7Bp%281-p%29%7D%7Bn%7D%7D%7D)
![Z = \dfrac{0.217- 0.28}{0.01}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cdfrac%7B0.217-%200.28%7D%7B0.01%7D)
Z = -6.3
24 cookies in total, probability of selecting sugar is 6/24 = 1/4 = 25%