To find the surface area of a pyramid, we need to find the area of all the faces and add them up.
4 * 6 = 24
24 / 2 = 12
There are four sides (not including the base) in this pyramid, so we should multiply this by 4.
12 * 4 = 48
Now, we find the area of the base.
6 * 6 = 36
We add up all of the numbers:
48 + 36 = 84
84 in^2 is the answer.
Hope this helps!
2(2)-3=5-2(2)
4-3=5-4
1=1
The correct answer is A
Answer:
<h2>
∠PZQ = 63°</h2>
Step-by-step explanation:
If point P is the interior of ∠OZQ , then the mathematical operation is true;
∠OZP + ∠PZQ = ∠OZQ
Given parameters
∠OZQ = 125°
∠OZP = 62°
Required
∠PZQ
TO get ∠PZQ, we will substitute the given parameters into the expression above as shown
∠OZP + ∠PZQ = ∠OZQ
62° + ∠PZQ = 125°
subtract 62° from both sides
62° + ∠PZQ - 62° = 125° - 62°
∠PZQ = 125° - 62°
∠PZQ = 63°
<em>Hence the value of ∠PZQ is 63°</em>
Answer:
Step-by-step explanation:
The average scores s (on a 100 point scale) for the students can be modeled by
s = 75 - 6 In(t + 1), 0 < t < 12
where t is the time in months.
a) Since the students were given an exam and then retested monthly with equivalent exams, then,
For the original exam, t = 0
Therefore,
s = 75 - 6 In(0 + 1) = 75 - 6 In1
s = 75 - 6 × 0 = 75
b) the average score after 4 months, t = 4
Therefore,
s = 75 - 6 In(4 + 1) = 75 - 6 In5
s = 75 - 9.66 = 65.34
c) s = 60
Therefore,
60 = 75 - 6 In(t + 1)
6 In(t + 1) = 75 - 60 = 15
In(t + 1) = 15/6 = 2.5
t + 1 = e^2.5 = 12.18
t = 12.18 - 1 = 11.18
t = 11 approximately
Answer:
Around 11.9
Step-by-step explanation:
5.3n + 7.75 = 70.85
First subtract 7.75 on both sides.
5.3n = 63.1
Then divide both sides by 5.3
n=11.9 (I rounded to the nearest tenth.)
