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Tema [17]
4 years ago
14

What is the missing exponent? 64/81 = (8/9)?.

Mathematics
2 answers:
Marat540 [252]4 years ago
6 0
Let the ?=x
We have
\frac{64}{81} =  \frac{8}{9}^x
\frac{2^6}{3^4}=( \frac{2^3}{3^2} )^x=(\frac{2^3}{3^2})^2=( \frac{2^3}{3^2} )^x
2=x
Aleks [24]4 years ago
4 0
Try and divide
if (8/9)^m=(64/81), then (8/9) must be a factor of 64/81

basically, if x^m=y, then divide y by x untill you get x

divide top by 8 and bottom by 9 to reverse it
we get 8/9
so therefor 8/9 ties 8/9=64/81
therfor the missing exponent is 2
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