Answer:
The sum of three angles in triangles are 180 degrees so
if there is triangle ABC,
A+B+C=180
A+38+38=180
A=104
Let stadium 1 be the one on the left and stadium 2 the one on the right.
Angle above stadium 1 is 72.9° and the angle above stadium 2 is 34.1° using the angle property of alternate angles(because both the ground and the dotted line are parallel).
For the next part we need to use the trigonometric function of tangent.
As tan x = opposite / adjacent,
Tan 72.9°=1500/ adjacent ( the ground from O to stadium 1)
Therefore the adjacent is 1500/tan 72.9°= 461.46 m( to 5 s.f.)
Same for the next angle,
Tan 34.1°=1500/ adjacent ( the ground from O to stadium 2)
Therefore, the adjacent is 1500/tan 34.1° = 2215.49 m (to 5 s.f.)
Thus, the distance between both stadiums is 2215.49-461.46= 1754.03 m
Correcting the answer to whole number gives you 1754 m which is the option C.
Answer:
f=2/3
Step-by-step explanation:
Answer:
The correct option is the graph on the bottom right whose screen grab is attached (please find)
Step-by-step explanation:
The information given are;
The required model height for the designed clothes should be less than or equal to 5 feet 10 inches
The equation for the variance in height is of the straight line form;
y = m·x + c
Where x is the height in inches
Given that the maximum height allowable is 70 inches, when x = 0 we have;
y = m·0 + c = 70
Therefore, c = 70
Also when the variance = 0 the maximum height should be 70 which gives the x and y-intercepts as 70 and 70 respectively such that m = 1
The equation becomes;
y ≤ x + 70
Also when x > 70, we have y ≤
-x + 70
with a slope of -1
To graph an inequality, we shade the area of interest which in this case of ≤ is on the lower side of the solid line and the graph that can be used to determine the possible variance levels that would result in an acceptable height is the bottom right inequality graph.
Answer: 123
They have to add up to 3 4 5 6 or 7 so it has to be that