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Bond [772]
4 years ago
14

A cylinder and a cone each have a radius of 3 in. and a height of 8 in. What is the ratio of the volume of the cone to the volum

e of the cylinder?
Question 20 options:

Vcone : Vcylinder = 1:3


Vcone : Vcylinder = 1:2


Vcone : Vcylinder = 1:1


Vcone : Vcylinder = 1:π
Mathematics
1 answer:
a_sh-v [17]4 years ago
5 0
I think for this answer it would be the third option. This is because to find the volume of both figures, the formula would be v=bh. they both have the same formulas and are both in proportion to each other. once you calculate the volume you will come to find that the answer is the same. this would make it 1 to 1
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Taylor has $32000 a part of which he invested at 5% and the remainder at 3%. His annual return on each investment is the same. A
ki77a [65]

Taylor have to invest the total money at 3.75%

Step-by-step explanation:

Let the part of money invested at 5% be 'a' and the part of money invested at 3% be (32000-a).

To find (a) :

The annual income for both the 5% and 3% investment is equal.

Interest= (amount x rate of interest x time) /100

Interest for 5% rate on investment

Interest = (a x 5 x 1) /100

Interest for 3% rate on investment

Interest = [(32000-a) x 3 x 1]/100

Both the interests are equal so equate both the equations.

(a x 5 x 1) /100 = [(32000-a) x 3 x 1] /100

5a = (32000-a) 3

5a = 96000-3a

8a = 96000

a = 96000/8

a = 12000

32000-a = 32000-12000

= 20000

The amount invested at 5% is $12000 and invested $20000 at 3%

Interest = (12000 x 5 x 1) /100

= 60000/100

= $600

Interest = (20000 x 3 x 1) /100

= 60000/100

= $600

Total interest = $1200

To find the rate at which the total money is to be invested to get the same annual income.

1200 = (32000 x rate x 1) /100

1200 x 100 = 32000 x rate x 1

120000 = 32000 x rate

120000/32000 = rate

Rate = 3.75%

Taylor have to invest the total money at 3.75% to get the same annual income

4 0
3 years ago
Help ill give brainliest and 5 star and thx if u help with all of em and ill give 20 points
choli [55]

Answer:

1. 3mg

2. 3050g

3. 0.025g

4. 5700mg

5. 0.294g

6. 32mg

7. 13700mg

8. 2.441kg

9. 8.24g

10. 0.075kg

11. 430g

12. 0.721g

Step-by-step explanation:

This should be right :)

3 0
3 years ago
23/10 as a decimal pleas help now
Arlecino [84]

Answer:

2.3

Step-by-step explanation:

To convert a fraction to a decimal you must divide the numerator by the denominator. By doing so, you receive the decimal of 2.3

7 0
3 years ago
Read 2 more answers
How many milliliters of 0.30%. sugar solution must you add to 75 mL of 4% sugar solution to get a 0.50% sugar solution? show you
LekaFEV [45]
<span>We have 75 mL of 4% sugar solution.
We have to add a 30% sugar </span><span>solution to make a 50% </span><span>sugar solution.
75 * .04 + .30x = .50 * (75 +x)
3 + .30x = 37.5 +.50x
I can't get the equation to solve.
Did you type it correctly? For one thing, you have the percentages typed as .30 % and 4%.  Are the decimal places in the correct positions?

Also, no matter how much 30% sugar solution you add, it will NEVER increase to 50%.


</span>
6 0
3 years ago
Write equations for the horizontal and vertical lines passing through the point (6,9)​
Maslowich

The equations for the horizontal and vertical lines passing through the point (6,9)​ is y = 9 and x = 6 respectively

<u>Solution:</u>

Given, point is (6, 9)

We have to find the equations for horizontal and vertical lines passing through above given point.

Now, let us find horizontal line,  

We know that, horizontal line is parallel to x – axis, so slope of our required line is 0.

The point slope form is given as y - y_1 = m(x - x_1)

Then, line equation in point slope form ⇒ y – 9 = 0(x – 6)

⇒ y – 9 = 0

⇒ y = 9

Now, let us find vertical line,

We know that, vertical line is parallel to y – axis, so slope of our required line is undefined (\frac{1}{0})

Then, line equation in point slope form ⇒ y-9=\frac{1}{0}(x-6)

⇒ x – 6 = 0(y – 9)

⇒ x – 6 = 0

⇒ x = 6

Hence, the horizontal line equation is y = 9 and vertical line equation is x = 6.

7 0
3 years ago
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