5x^2=60
(5x^2=60)/5
x^2=12
√(x^2)=√12
x=+/-√12
We have the following function:
p (x) = - 2 (x-9) ^ 2 +200
We derive to find the maximum of the function:
p '(x) = - 4 (x-9)
Rewriting:
p '(x) = - 4x + 36
We match zero:
-4x + 36 = 0
We clear x
x = 36/4
x = 9 degrees
The maximum population occurs when x = 9.
We evaluate the function for this value:
p (9) = - 2 * (9-9) ^ 2 +200
p (9) = 200
Answer:
The maximum number of fish is:
p (9) = 200
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Answer:
The diagram is attached below.
Step-by-step explanation:
A normal distribution mean 0 and standard deviation 1 is known as the standard normal distribution.
So, the readings on the thermometers (denoted by <em>Z</em>) follows N (0, 1).
It is provided that 2.7% of the thermometers are rejected because they have readings that are too high and 2.7% are rejected because they have readings that are too low.
This implies that:

The value of <em>z</em> associated to both these probabilities are:
<em>z</em> = 1.93.
That is,

*Use a <em>z</em>-table.
The diagram for the two readings that are cutoff values separating the rejected thermometers from the others is attached below.