Answer:
Cost of equipment after n years = 300000 x 0.86ⁿ
Step-by-step explanation:
A construction company purchased some equipment costing $300,000.
Price of equipment = 300000 $
The value of the equipment depreciates (decreases) at a rate of 14% per year.
Let c(n) be the cost of equipment after n years.
Cost of equipment after n years = 300000 x 0.86ⁿ
Answer:
length = 100 width = 50
Thus, the length is twice the width (50 width x 2 = 100 which is the length)
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
The circumference of a circle can be described as the linear distance round the circle
The circumference of a circle = 2πr or πD
π = 3.14
r = radius
d = diameter
the diameter is the straight line that passes through the centre of a circle and touches the two edges of the circle.
π = circumference / 2r or circumference / D
37.68 / 12
Answer:
Account A = $ 96.80
Account B = $ 48.40
Step-by-step explanation:
Account A
Principal = $1,000
rate = 2.42% = 0.0242
time = 4 years
To find the interest we will use the formula :
I = PTR
I = 1000 x 4 x 0.0242
I = $96.80
Account B
P = 1,000
t = 24 months = 2 years
r = 2.42% = 0.0242
I = PTR
I = 1000 x 2 x 0.0242
I = $ 48. 40
difference in interest = Interest a - Interest b
difference = 96.80 - 48.40
difference = $ 48 . 40
The interest on Account A doubles the interest on Account B
<span>let x be the first integer, then
:
x + (x+1) + (x+2) + (x+3) + (x+4) + (x+5) = 519
:
6x + 15 = 519
:
6x = 504
:
x = 84</span>
