The sum of 6 consecutive integers is 519. What is the third number in this sequence?
2 answers:
<span>let x be the first integer, then : x + (x+1) + (x+2) + (x+3) + (x+4) + (x+5) = 519 : 6x + 15 = 519 : 6x = 504 : x = 84</span>
<span>6 consecutive integers x, x+1, x+2, x+3, x+4, x+5 </span><span>sum of 6 consecutive integers is 519 </span>x+ x+1+ x+2+ x+3+ x+4+ x+5 = 519 <span>6x + 15 = 519 6x = 504 x = 84 </span><span>84 +1 = 85 84 +2 = 86 84 +3 = 87 84 +4 = 88 84 +5 = 89 </span><span> answer:</span> third number in this sequence = 86<span> </span>
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